Question

我有一个上传代码的文件。一切都很好，但我想在加载文件时重命名该文件。我的代码在这里。我只需要重命名功能和它应该放在哪里。这段代码非常长，因为将大图像裁剪得很小。

示例：如果文件为10MB，则为40或50 KB

error_reporting(0);
$change = "";
$abc = "";
define("MAX_SIZE", "400");

function getExtension($str) {
    $i = strrpos($str, ".");
    if (!$i) {
        return "";
    } $l = strlen($str) - $i;
    $ext = substr($str, $i + 1, $l);
    return $ext;
}

$errors = 0;
if ($_SERVER["REQUEST_METHOD"] == "POST") {
    $image = $_FILES["file"]["name"];
    $uploadedfile = $_FILES['file']['tmp_name'];
    if ($image) {
        $filename = stripslashes($_FILES['file']['name']);
        $extension = getExtension($filename);
        $extension = strtolower($extension);
        if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) {
            $change = '<div class="msgdiv">Unknown Image extension</div>';
            $errors = 1;
        } else {
            $size = filesize($_FILES['file']['tmp_name']);
            if ($size > MAX_SIZE * 1024) {
                $change = '<div class="msgdiv">You have exceeded the size limit!</div>';
                $errors = 1;
            } if ($extension == "jpg" || $extension == "jpeg") {
                $uploadedfile = $_FILES['file']['tmp_name'];
                $src = imagecreatefromjpeg($uploadedfile);
            } else if ($extension == "png") {
                $uploadedfile = $_FILES['file']['tmp_name'];
                $src = imagecreatefrompng($uploadedfile);
            } else {
                $src = imagecreatefromgif($uploadedfile);
            } echo $scr;
            list($width, $height) = getimagesize($uploadedfile);
            $newwidth = 280;
            $newheight = ($height / $width) * $newwidth;
            $tmp = imagecreatetruecolor($newwidth, $newheight);
            imagecopyresampled($tmp, $src, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
            $filename = "../adimages/" . $_FILES['file']['name'];
            imagejpeg($tmp, $filename, 100);
            imagedestroy($src);
            imagedestroy($tmp);
            imagedestroy($tmp1);
        }
    }
}

Answer 1

只需使用您想要的名称而不是$_FILES['file']['name']

例如：

$filename = "../adimages/". time();

这将使用当前时间戳为每个上传的文件命名。

Answer 2

更改您的以下内容

$filename = "../adimages/" . $_FILES['file']['name'];

以下内容： -

$new_name = "new_file_name".time();
$filename = "../adimages/" . $new_name;

为唯一性添加了

time（）。在 new_file_name 的地方，您还可以输入 $ _ FILES ['file'] ['name'] ;

Answer 3

试试这个 - 只需更换你的行

$filename = "../adimages/" . $_FILES['file']['name'];

使用这个新行

$filename = "../adimages/" .time().'.'.$extension ;

如何上传重命名文件？

3 个答案: