Question

我有这个普通的expressjs app.js

/**
 * Module dependencies.
 */

var express = require('express');
var routes = require('./routes');
var user = require('./routes/user');
var http = require('http');
var path = require('path');

var app = express();

// all environments
app.set('port', process.env.PORT || 3000);
app.set('views', path.join(__dirname, 'views'));
app.set('view engine', 'jade');
app.use(express.favicon());
app.use(express.logger('dev'));
app.use(express.json());
app.use(express.urlencoded());
app.use(express.methodOverride());
app.use(app.router);
app.use(express.static(path.join(__dirname, 'public')));

// development only
if ('development' == app.get('env')) {
  app.use(express.errorHandler());
}

app.get('/', routes.index);
app.get('/users', user.list);

http.createServer(app).listen(app.get('port'), function(){
  console.log('Express server listening on port ' + app.get('port'));
});

我要删除

app.get('/', routes.index);
app.get('/users', user.list);

并将它们放在一个单独的文件中。我正在尝试这个

module.exports = function(/* any dependency? */){
 app.get('/', routes.index);
app.get('/users', user.list);
}

并在app.js文件中我有require('./routed.js');

但这不起作用。我该如何解决这个问题？。

Answer 1

我接受了krasu的回答并修改了一下

routed.js

var routes = require('./routes');
var user = require('./routes/user');

module.exports = function(app){
 app.get('/', routes.index);
 app.get('/users', user.list);
}

app.js

中的

require('./routed.js')(app);

这可行。

Answer 2

试试这个：

app.use(express.static(path.join(__dirname, 'public')));

require('./routed.js')(app);

并在./routed.js

module.exports = function(app){
 app.get('/', routes.index);
 app.get('/users', user.list);
}

将app.get（）路由放在单独的文件中

2 个答案: