Question

我有一个搜索表单，其中包含四个过滤器文本框。我想要做的是每当用户提交表单时，只会提交和搜索具有值的文本框。我知道如何在if语句中执行它，但是在代码中编写它太长了。还有其他更短的方法吗？

Answer 1

Process.php

<?php


if (($_POST['First'])== TRUE);
 $Fv = $_POST['First'];
if(($_POST['Second'])== TRUE);
$Sv = $_POST['Second'];
if(($_POST['Third'])!= TRUE);
$Tv = $_POST['Third'];
if(($_POST['Fourth'])!= TRUE);
$Fov = $_POST['Fourth'];

echo $Fv;
echo"</br>";
echo $Sv;
echo"</br>";
echo $Tv;
echo"</br>";
echo $Fov;

?>

的search.php

<?php

echo '<html>
<body>

<form action="process.php" method="post">
First: <input type="text" name="First"><br>
Second: <input type="text" name="Second"><br>
Third: <input type="text" name="Third"><br>
Fourth: <input type="text" name="Fourth"><br>

<input type="submit">
</form>

</body>
</html> ';
?>

仅回输输入的值。

Answer 2

试试这个的search.php

 $sql = " select * from table name where 1=1 "

   if (($_POST['First'])!='');
    $sql .= ' AND first = "'.$_POST['First'].'"';
   if(($_POST['Second'])!='');
    $sql .= ' AND Second = "'.$_POST['Second'].'"';
   if(($_POST['Third'])!='');
    $sql .= ' AND Third = "'.$_POST['Third'].'"';
   if(($_POST['Fourth'])!='');
    $sql .= ' AND Fourth = "'.$_POST['Fourth'].'"';

或试试这个

$arr = $_POST;
     $sql = " select * from table name where 1=1 "
     foreach($arr as $key =>$ar){
       if($ar!='')  $sql .= ' AND '.$key.' = "'.$ar.'"';
     }

输入名称和数据库字段名称必须相同...

Answer 3

尝试使用此代码。您可以在foreach循环中实现搜索条件。

// HTML field names
$fields = array_flip(array("search1", "search2", "search3", "search4"));

$data = array_filter(array_intersect_key($_POST, $fields));

foreach ($data as $key => $val) {
    // Here you can implement the sql search condtion
    echo "$key => $val" . PHP_EOL;
}

在php中动态获取数据

3 个答案: