Question

初始化，读取和写入安全令牌的小程序显示以下例外：

com.sun.deploy.security.BlockedException: User has denied the privileges to the code
sun.plugin2.applet.Plugin2ClassLoader.getPermissions(Unknown Source)
sun.plugin2.applet.Applet2ClassLoader.getPermissions(Unknown Source)
java.security.SecureClassLoader.getProtectionDomain(Unknown Source)
java.security.SecureClassLoader.defineClass(Unknown Source)
sun.plugin2.applet.Applet2ClassLoader.findClass(Unknown Source)
sun.plugin2.applet.Plugin2ClassLoader.loadClass0(Unknown Source)
sun.plugin2.applet.Plugin2ClassLoader.loadClass(Unknown Source)
sun.plugin2.applet.Plugin2ClassLoader.loadClass(Unknown Source)
java.lang.ClassLoader.loadClass(Unknown Source)

和

User has denied the privileges to the code

代码如下，JTextArea用于显示结果。

public static void test(final JTextArea textArea) throws Exception {
    AccessController.doPrivileged(new PrivilegedAction() {
        @Override
        public Object run() {
            try{
                final String label = "Test123";

                textArea.setText(textArea.getText() + "\n\n\t" + Misc.getMethod());
                initializeToken(textArea, label, "123456".toCharArray());

                textArea.setText(textArea.getText() + "\n\n\t\tinit OK");
                writeDataToToken(label, new byte[]{0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f}, "123456".toCharArray());
                textArea.setText(textArea.getText() + "\n\n\t\twrite OK");
                byte[] dataRead = readDataFromToken(label, "123456".toCharArray());
                for (byte i : dataRead) {
                    System.out.println((int) i);
                }
                textArea.setText(textArea.getText() + "\n\n\t\tread OK");
            }
            catch(Exception e){
                textArea.setText(textArea.getText() + "\n\n\t\t" + Misc.getStackTrace(e));
            }
            return null;
        }
    });
}

以下是HTML

中的applet代码

<applet code = 'test.GUI' 

    archive = 'TestApplet.jar, lib/TestLib.jar' 
    width = 700 
    height = 500>

    <resources>
        <nativelib href="nativeLib.dll"/>
    </resources>
    <param name="permissions" value="all-permissions" />
</applet>

appletPolicy.txt

Permissions: all-permissions
Application-Name: TestApplet
Codebase: https://www.localhost.com:8443/TestApplet.jar

...然后将其应用于applet jar TestApplet.jar并使用以下内容重新签名：

jar ufm dist\TestApplet.jar appletPolicy.txt
jar ufm dist\lib\TestLib.jar appletPolicy.txt

jarsigner dist\TestApplet.jar -keystore web.jks" web -storepass password
jarsigner dist\lib\TestLib.jar -keystore web.jks" web -storepass password

如何摆脱异常并使applet工作？

UPDATE ：文件IO操作没有问题 - 即使文件IO操作的代码不在AccessController.doPrivileged中，Applet也能够读取和写入而不会导致任何安全异常（）方法。

我也尝试过签署nativeLib.dll，但没有区别。

Applet - 由于安全性而无法工作。*例外

0 个答案: