Question

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLEncoder;

/**
 * Created by Kevin on 26/01/14.
 */
public final class Boot {

   public Boot(final String... args) {
       try {
           final URL url = new URL(args[0]);
           HttpURLConnection connection = (HttpURLConnection) url.openConnection();

           connection.setDoOutput(true);
           connection.setRequestMethod("POST");
           connection.addRequestProperty("Host", "http://example.com/");
           connection.addRequestProperty("Protocol", "HTTP/1.1");
           connection.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 6.3; WOW64; rv:26.0) Gecko/20100101 Firefox/26.0");
           connection.addRequestProperty("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
           connection.addRequestProperty("Referer", "http://example.com/");
           connection.setRequestProperty("Accept-Language", "en-US,en;q=0.5");
           connection.addRequestProperty("Cookie", "__cfduid=d2f9cfb1c350013cc71a12eaedc660a551390762958146; __utma=241386960.1917361281.1390762966.1390762966.1390762966.1; __utmb=241386960.1.10.1390762966; __utmc=241386960; __utmz=241386960.1390762966.1.1.utmcsr=(direct)|utmccn=(direct)|utmcmd=(none)");

           String encodedParams = URLEncoder.encode("login=true&email=kevin@example.com&pwd=mypassword");

           OutputStream wr = connection.getOutputStream();
           wr.write(encodedParams.getBytes());
           wr.flush();
           wr.close();

           final InputStreamReader isr = new InputStreamReader(connection.getInputStream(), "UTF-8");
           final BufferedReader br = new BufferedReader(isr);

           String line;
           while ((line = br.readLine()) != null) {
               System.out.println(line);
           }
           System.out.println("Response code: " + connection.getResponseCode());
           System.out.println(encodedParams);

       } catch (IOException e) {
           e.printStackTrace();
       }
   }

    public static void main(final String... args) {
        new Boot("https://www.example.com/admin/index.php");
    }
}

正如您在此处看到的代码，我正在尝试为网站的管理面板创建POST请求。但是，我想让它登录，所以打印出“管理仪表板”。

我一直在努力尝试超过2个小时而且我无法做到。尽管如此，这可能与Java有关吗？

Answer 1

当我在crosspost发布时，您可以使用HtmlUnit来避免编写所有代码。 getting started guide显示了登录的示例。

由于URL在参数中，因此您现在看起来像GET请求。

String encodedParams = URLEncoder.encode("login=true&email=kevin@example.com&pwd=mypassword");

或者，您可以尝试Apache Http Components库。

如何创建POST请求登录？

1 个答案: