Question

我以某种方式遇到了以下问题：我想要实现的是基于键合并以下数组：

{"Entities":{"submenu_id":"Parents","submenu_label":"parents"}}
{"Entities":{"submenu_id":"Insurers","submenu_label":"insurers"}}
{"Users":{"submenu_id":"New roles","submenu_label":"newrole"}}
{"Users":{"submenu_id":"User - roles","submenu_label":"user_roles"}}
{"Users":{"submenu_id":"Roles - permissions","submenu_label":"roles_permissions"}}
{"Accounting":{"submenu_id":"Input accounting data","submenu_label":"new_accounting"}}

需要像这样输出：

[{"item_header":"Entities"}, 
 {"list_items" :
    [{"submenu_id":"Parents","submenu_label":"parents"}, 
    {"submenu_id":"Insurers","submenu_label":"insurers"}]
}]
[{"item_header":"Users"}, 
 {"list_items" : 
    [{"submenu_id":"New roles","submenu_label":"newrole"}
    {"submenu_id":"User - roles","submenu_label":"user_roles"}
    {"submenu_id":"Roles - permissions","submenu_label":"roles_permissions"}]
}]
[{"item_header":"Accounting"}, 
 {"list_items" :
    [{"submenu_id":"Input accounting data","submenu_label":"new_accounting"}]
}]

过去两个小时我一直在尝试各种各样的事情，但是每次尝试都返回了不同的格式，因此失败了。不知何故，我无法弄清楚为了完成这项工作，你有建设吗？
我很想知道你对此事的看法。

感谢。

Answer 1

$input = array(
    '{"Entities":{"submenu_id":"Parents","submenu_label":"parents"}}',
    '{"Entities":{"submenu_id":"Insurers","submenu_label":"insurers"}}',
    '{"Users":{"submenu_id":"New roles","submenu_label":"newrole"}}',
    '{"Users":{"submenu_id":"User - roles","submenu_label":"user_roles"}}',
    '{"Users":{"submenu_id":"Roles - permissions","submenu_label":"roles_permissions"}}',
    '{"Accounting":{"submenu_id":"Input accounting data","submenu_label":"new_accounting"}}',
);

$input = array_map(function ($e) { return json_decode($e, true); }, $input);

$result = array();
$indexMap = array();
foreach ($input as $index => $values) {
    foreach ($values as $k => $value) {
        $index = isset($indexMap[$k]) ? $indexMap[$k] : $index;
        if (!isset($result[$index]['item_header'])) {
            $result[$index]['item_header'] = $k;
            $indexMap[$k] = $index;
        }
        $result[$index]['list_items'][] = $value;
    }
}
echo json_encode($result);

Answer 2

我更喜欢OO方法。

首先是list_item的一个对象：

{"submenu_id":"Parents","submenu_label":"parents"}

第二个item_header的对象：

{"item_header":"Entities", "list_items" : <array of list_item> }

最后一个对象或数组：

{ "Menus: <array of item_header> }

相应的getter / setter等。

Answer 3

以下代码将为您提供必要的数组，您可以通过该数组进行迭代以获得所需的输出。

$final_array = array();  
foreach($array as $value) { //assuming that the original arrays are stored inside another array. You can replace the iterator over the array to an iterator over input from file       
    $key  =  /*Extract the key from the string ($value)*/
    $existing_array_for_key = $final_array[$key];
    if(!array_key_exists ($key , $final_array)) {
        $existing_array_for_key = array();
    }
    $existing_array_for_key[count($existing_array_for_key)+1] = /*Extract value from the String ($value)*/
    $final_array[$key] = $existing_array_for_key;
}

Answer 4

你在这里！在这种情况下，首先我将所有数组添加到一个数组中进行处理我以为他们先是在同一个阵列，但现在我意识到他们不是。只需填空$array=[]，然后将其全部添加到$array[]=$a1，$array[]=$a2等中......

   $array = '[{"Entities":{"submenu_id":"Parents","submenu_label":"parents"}},
   {"Entities":{"submenu_id":"Insurers","submenu_label":"insurers"}},
   {"Users":{"submenu_id":"New roles","submenu_label":"newrole"}},
   {"Users":{"submenu_id":"User - roles","submenu_label":"user_roles"}},
   {"Users":{"submenu_id":"Roles - permissions","submenu_label":"roles_permissions"}},
   {"Accounting":{"submenu_id":"Input accounting data","submenu_label":"new_accounting"}}]';

   $array = json_decode($array, true);


    $intermediate = []; // 1st step

    foreach($array as $a)
    {
       $keys = array_keys($a);
       $key = $keys[0]; // say, "Entities" or "Users"
       $intermediate[$key] []= $a[$key];
    }

    $result = []; // 2nd step

    foreach($intermediate as $key=>$a)
    {
       $entry = ["item_header" => $key, "list_items" => [] ];
       foreach($a as $item) $entry["list_items"] []= $item;
       $result []= $entry;
    }

    print_r($result);

PHP无法获得正确的数组格式

4 个答案: