我有一个JsonConverter
,根据实例特定的标志,需要
如何从JsonConverter
?
由于
答案 0 :(得分:12)
这是一个例子。假设您的类序列化如下所示:
class Foo
{
public bool IsSpecial { get; set; }
public string A { get; set; }
public string B { get; set; }
public string C { get; set; }
}
IsSpecial
标志用于控制我们是否在转换器中执行某些特殊操作,或者只是自然地序列化。您可以像这样编写转换器:
class FooConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return typeof(Foo).IsAssignableFrom(objectType);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
Foo foo = (Foo)value;
JObject jo;
if (foo.IsSpecial)
{
// special serialization logic based on instance-specific flag
jo = new JObject();
jo.Add("names", string.Join(", ", new string[] { foo.A, foo.B, foo.C }));
}
else
{
// normal serialization
jo = JObject.FromObject(foo);
}
jo.WriteTo(writer);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
然后,要使用转换器,请将其实例传递给SerializeObject
方法(例如,在设置中)。 (不要使用JsonConverter
属性装饰目标类,否则在序列化时会导致无限递归循环。)
class Program
{
static void Main(string[] args)
{
List<Foo> foos = new List<Foo>
{
new Foo
{
A = "Moe",
B = "Larry",
C = "Curly",
IsSpecial = false
},
new Foo
{
A = "Huey",
B = "Dewey",
C = "Louie",
IsSpecial = true
},
};
JsonSerializerSettings settings = new JsonSerializerSettings();
settings.Converters.Add(new FooConverter());
settings.Formatting = Formatting.Indented;
string json = JsonConvert.SerializeObject(foos, settings);
Console.WriteLine(json);
}
}
输出:
[
{
"IsSpecial": false,
"A": "Moe",
"B": "Larry",
"C": "Curly"
},
{
"names": "Huey, Dewey, Louie"
}
]
答案 1 :(得分:4)
您可以更改CanWrite属性以禁用自定义序列化程序。如果对象可以包含相同类型的子节点,或者您要在多个线程中进行序列化,则无法正常工作。
class FooConverter : JsonConverter
{
bool _canWrite = true;
public override bool CanWrite
{
get { return _canWrite;}
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
Foo foo = (Foo)value;
JObject jo;
if (foo.IsSpecial)
{
// special serialization logic based on instance-specific flag
jo = new JObject();
jo.Add("names", string.Join(", ", new string[] { foo.A, foo.B, foo.C }));
}
else
{
// normal serialization
_canWrite = false;
jo = JObject.FromObject(foo);
_canWrite = true;
}
jo.WriteTo(writer);
}
}