Question

我制作了一个php函数，计算从现在到52周的几周，然后从第1周开始再次向左开始几周。

我想知道是否有更简单的方法来做到这一点，或者我做了一个正确的功能。

这是我的代码：

function weeks($start_week)
                {

                    $start_week     = str_replace("0", "", $start_week); // from week 1 tot 9 remove the zero's.
                    $offset_week    = $start_week - 1; // when the loop reach week 52, start with new weeks minus 1
                    $last_week      = 52; // Last week of the year

                    $aantal_weken   = 52; // # of weeks in a year

                    for($start_week; $start_week <= $aantal_weken; $start_week++)
                    {
                        echo $start_week.", ";

                        if($start_week == $last_week)
                        {   
                            $new_weeks = 1; // when we reach week 52, set a new variable tot first week of the year

                            for($new_weeks; $new_weeks <= $offset_week; $new_weeks++)
                            {
                                echo $new_weeks.", ";                           
                            }
                        }
                    }

                    return $start_week;
                }

                $date = date("W");
                weeks($date);

输出：

4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27 ，28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52 ，1,2,3，

Answer 1

返回数周范围的数组：

function weeks($start_week) {
    $last_week = date_format(date_create('December 28th'), 'W');
    $range = range(1, $last_week);
    return array_merge(
        array_slice($range, $start_week - 1), 
        array_slice($range, 0, $start_week - 1)
    );
}

demo

Answer 2

您的问题实际上与日期无关。它只与数学有关。请尝试以下代码：

function weeks($start_week) {
    $arr = array();
    for ($i = 0; $i < 52; $i++) {
        $arr[] = ($i + $start_week - 1) % 52 + 1;
    }
    return implode(', ', $arr);
}
echo weeks(4);

Answer 3

function weeks($start_week)
{
    $start_week     = str_replace("0", "", $start_week); // from week 1 tot 9 remove the zero's.
    $offset_week    = $start_week - 1; // when the loop reach week 52, start with new weeks minus 1
    $last_week      = 52; // Last week of the year
    $aantal_weken   = 52; // # of weeks in a year

    for($start_week; $start_week <= $aantal_weken; $start_week++)
    {
        echo $start_week.", ";

        if($start_week == $last_week)
        {   
            $new_weeks = 1; // when we reach week 52, set a new variable tot first week of the year

            for($new_weeks; $new_weeks <= $offset_week; $new_weeks++)
            {
                echo $new_weeks.", ";                           
            }
        }
    }

    return $start_week;
}

$date = date("W");
weeks($date);

第5周到第52周，然后第1周到第4周总共52周

3 个答案: