Question

我有一个包含以下代码的表单：

<form action="doRegister" class="form-signup" >

    <h2 class="form-signup-heading">Please sign up</h2>
    <input type="email" class="form-control" placeholder="Email address" required autofocus>
    <input type="password" class="form-control" placeholder="Password" required>
    <input type="password" class="form-control" placeholder="Password control" required>
    <input type="text" class="form-control" placeholder="Name" required>
    <input type="text" class="form-control" placeholder="Surname" required>
    <input type="date" class="form-control" placeholder="Born date" required>

    <button class="btn btn-lg btn-primary btn-block" type="submit">Sign up</button>
</form

我有两个课程：UserRegisterForm和UserRegistrationAction

UserRegisterForm

package com.github.jcpp.jathenaeum.action;

import org.apache.struts.action.ActionForm;

public class UserRegisterForm extends ActionForm{

    private static final long serialVersionUID = 1;

    /*ATTRIBUTES of the form fields*/

    /*METHODS Get and Set*/

    public UserRegisterForm() {
        super();
    }
}

UserRegistrationAction

package com.github.jcpp.jathenaeum.action;

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;

import com.github.jcpp.jathenaeum.Utente;
import com.github.jcpp.jathenaeum.db.dao.UtenteDAO;
import com.github.jcpp.jathenaeum.exceptions.RegistrationException;

public class UserRegistrationAction extends Action{

    @Override
    public ActionForward execute(ActionMapping mapping, ActionForm form,
            HttpServletRequest request, HttpServletResponse response)
            throws Exception {

        //boolean action_perform = false;
        String action_target = null;
        Random rnd = new Random();
        UtenteDAO userDao = new UtenteDAO();

        Utente user = new Utente();
        //ActionMessages errors_mesg = new ActionMessages();
        UserRegisterForm uf = (UserRegisterForm) form;
        if(form != null){
            user.setEmail(uf.getEmail());
            user.setPassword(uf.getPassword());
            user.setNome(uf.getName());
            user.setCognome(uf.getSurname());
            user.setDataNascita(uf.getBornDate());
            user.setNumeroTessera(rnd.nextInt(999999)+1);


            try{
                if(userDao.register(user)){
                    action_target = "success";
                }

            }catch(Exception e){
                action_target = "failed";
                throw new RegistrationException();
            }
        }

        return mapping.findForward(action_target);
    }

在我的struts-config.xml我：

<form-beans>
        <form-bean name="registerform" type="com.github.jcpp.jathenaeum.action.UserRegisterForm"/>
</form-beans>

<action-mappings>
        <action path="/index" type="org.apache.struts.actions.ForwardAction" parameter="page.index" />
        <action path="/signin" type="org.apache.struts.actions.ForwardAction" parameter="page.signin" />
        <action path="/signup" type="org.apache.struts.actions.ForwardAction" parameter="page.signup" />
        <action
                path="/doRegister"
                type="com.github.jcpp.jathenaeum.action.UserRegistrationAction"
                name="registerform"
                scope="request"
                validate="true"
                input="signup">
                <forward name="input" path="/index.jsp"/>
                <forward name="success" path="/welcome.jsp"/>
                <forward name="failure" path="/index.jsp"/>
            </action>
    </action-mappings>

我的错误报告是：

类型状态报告
消息 / JAthenaeum / doRegister
说明请求的资源不可用。

为什么我会遇到这个问题？

Answer 1

该操作会返回名为"failed"的未知转发。将其更改为配置为操作"failure"的配置。以下代码应替换

try {
  if(!userDao.register(user)) {
     return mapping.findForward("failure");
  }
}catch(Exception e){
   throw new RegistrationException(e);
}

return mapping.findForward("success");

异常应提供更多信息，告诉您异常的原因。

此外，表单应映射到操作权

<html:form action="/doRegister" cssClass="form-signup" >

Answer 2

问题在于表单中的操作参数：在我的情况下它必须是doRegister.do，在struts-config.xml中，操作路径等于/doRegister 。因此，请参阅以下代码：

<form action="doRegister.do" >
[...]
</form>

和struts-config.xml

<action
                path="/doRegister" <!-- LOOK HERE -->
                type="com.github.jcpp.jathenaeum.action.UserRegistrationAction"
                name="registerform"
                scope="request"
                validate="true"
                input="/signup.jsp">
               <!-- <forward name="input" path="/index.jsp"/>
                <forward name="success" path="/signin.jsp"/>
                <forward name="failed" path="/signup.jsp"/> -->
            </action>

如何将我的表单与动作相关联？

2 个答案: