MySQL选择具有两个条件的行，并使用相同的列ID计数大于1的行

Question

在此示例中，结果应为conversation_id 165337：

这是我到目前为止所使用的MySQL不起作用：

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id              
FROM xf_conversation_recipient
WHERE user_id = '4465'
AND user_id = '1'
HAVING COUNT(DISTINCT conversation_id) > 1
");

以下是有效的答案和代码：

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient
WHERE user_id IN ('4465','1') 
GROUP BY conversation_id HAVING c > 1
");

Answer 1

然后试试这个：

SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient  
GROUP BY conversation_id HAVING c > 1;

，在你的情况下：

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id, COUNT(*) c 
FROM xf_conversation_recipient
WHERE user_id IN ('4465','1') 
GROUP BY conversation_id HAVING c > 1
");

Answer 2

WHERE user_id = '4465' AND user_id = '1' 

正确

WHERE user_id  = '4465' OR user_id = '1' 

Answer 3

$value1 = $this->_getDb()->fetchCol("
SELECT conversation_id FROM xf_conversation_recipient WHERE user_id IN ('4465','1') HAVING COUNT(*) > 1
");