Question

我是Java Web-Services的新手，我正在尝试使用我的Eclipse IDE使用Jersey实现并在Apache Tomcat 6.0上部署应用程序作为Eclipse的插件来实现一个简单的JAX-RS示例。我按照书java web services up and running

中给出的示例进行操作

我创建了一个JAX-RS Application：

package adages;

import java.util.Set;
import java.util.HashSet;
import javax.ws.rs.ApplicationPath;
import javax.ws.rs.core.Application;
@ApplicationPath("/resourcesA")
public class RestfulAdage extends Application {
    @Override
    public Set<Class<?>> getClasses() {
    Set<Class<?>> set = new HashSet<Class<?>>();
        set.add(Adages.class);
        return set;
    }
}

和JAX-RS resource：

package adages;

import javax.xml.bind.annotation.XmlElementDecl;
import javax.xml.bind.JAXBElement;
import javax.xml.namespace.QName;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import java.util.Random;
import com.fasterxml.jackson.databind.ObjectMapper;

@Path("/")
public class Adages {

    private String[] aphorisms = {"What can be shown cannot be said.",
        "If a lion could talk, we could not understand him."};

    public Adages() {
    }

    @GET
    @Produces({ MediaType.APPLICATION_XML })
    public JAXBElement<Adage> getXml() {
        return toXml(createAdage());
    }

    @GET
    @Produces({ MediaType.APPLICATION_JSON })
    @Path("/json")
    public String getJson() {
        return toJson(createAdage());
    }

    @GET
    @Produces({ MediaType.TEXT_PLAIN })
    @Path("/plain")
    public String getPlain() {
        return createAdage().toString() + "\n";
    }

    // Create an Adage and set the words property, which
    // likewise sets the wordCount property. The adage is
    // randomly selected from the array, aphorisms.
    private Adage createAdage() {
        Adage adage = new Adage();
        adage.setWords(aphorisms[new Random().nextInt(aphorisms.length)]);
        return adage;
    }

    // Java Adage --> XML document
    @XmlElementDecl(namespace = "http://aphorism.adage", name = "adage")
    private JAXBElement<Adage> toXml(Adage adage) {
        return new JAXBElement<Adage>(new QName("adage"), Adage.class, adage);
    }

    // Java Adage --> JSON document
    // Jersey provides automatic conversion to JSON using the Jackson
    // libraries. In this example, the conversion is done manually
    // with the Jackon libraries just to indicate how straightforward it is.
    private String toJson(Adage adage) {
        String json = "If you see this, there's a problem.";
        try {
            json = new ObjectMapper().writeValueAsString(adage);
        } catch (Exception e) {
        }
        return json;
    }
}

和我的POJO班级：

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "adage")
public class Adage {
    protected String words;
    protected int wordCount;

    public Adage() {
    }

// overrides
@Override
public String toString() {
        return words + " -- " + wordCount + " words";
    }
           // Setters & Getters
}

web.xml文件包含：

<servlet>
    <servlet-name>jersey</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>adages</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

当我将我的应用程序部署到Tomcat服务器时，我在日志中看到以下消息：

INFO: Starting Servlet Engine: Apache Tomcat/6.0.36
Jan 26, 2014 10:19:03 AM com.sun.jersey.api.core.PackagesResourceConfig init
INFO: Scanning for root resource and provider classes in the packages:
  adages
Jan 26, 2014 10:19:03 AM com.sun.jersey.api.core.ScanningResourceConfig logClasses
INFO: Root resource classes found:
  class adages.Adages
Jan 26, 2014 10:19:03 AM com.sun.jersey.api.core.ScanningResourceConfig init
INFO: No provider classes found.
Jan 26, 2014 10:19:03 AM com.sun.jersey.server.impl.application.WebApplicationImpl _initiate
INFO: Initiating Jersey application, version 'Jersey: 1.10 11/02/2011 03:53 PM'

它说“找不到提供者类”。

当我尝试访问网址 - http://localhost:8080/rest/resourcesA/时，我收到以下错误：

HTTP Status 404 - /rest/resourcesA/

这里“休息”是我日食项目的名称。在这个例子中，请帮助我在哪里做错了？

我已经阅读了这篇文章：404 when accessing Jersey app in Tomcat 7，但我仍面临同样的问题。

这是一个非常基本的例子，我坚持为什么它不起作用，经历过几个帖子但是我无法弄清楚这个问题，请让我知道我在哪里做错了？

Answer 1

进一步浏览后，我现在能够解决问题。

1）不需要RestfulAdage类，所以我删除了它。

2）更新了我的web.xml文件，以获得泽西岛ServletContainer

的网址映射

<servlet-mapping>
   <servlet-name>jersey</servlet-name>
   <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

现在以http://localhost:8080/rest/rest方式访问网址会调用方法public JAXBElement<Adage> getXml()

并以http://localhost:8080/rest/rest/plain方式访问网址，成功调用了方法public String getPlain()。

Jersey JAX RS错误 - 未找到提供程序类

1 个答案: