Question

所以我在使用以下代码删除行时遇到问题。该表正确显示信息，并在url中将正确的id发送到delete.php页面，但我无法完成命令。在delete.php稍微更改代码我可以让它显示：

无法删除索引。

或：

绑定参数失败：0

    <?php
$con = mysqli_connect("localhost","user","pass","database");
// Check connection
if (mysqli_connect_errno())
{
    die("Failed to connect to MySQL: " . mysqli_connect_error());
}

if (!$result = mysqli_query($con,"SELECT * FROM mytable ORDER BY `server_name`;"))
{
    die("Error: " . mysqli_error($con));
}
?>
<table border='1'>
<tr>
<th><b>Server Name</b></th>
<th><center><b>Port</b></center></th>
<th><center><b>Mod</b></center></th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row['server_name']; ?></td>
<td><center><?php echo $row['server_port']; ?></center></td>
<td><center><?php echo $row['mod']; ?></center></td>
<td><center><a href="delete.php?id=<?php echo $row['index']; ?>"><img src="images/remove.png" width="16" height="16"></center></img></a></td>
</tr>
<?php
}
mysqli_close($con);
?>
</table>

我的删除文件是

    <?php
// Your database info
$db_host = 'localhost';
$db_user = 'user';
$db_pass = 'pass';
$db_name = 'database';

if (!isset($_GET['id']))
{
    echo 'No ID was given...';
    exit;
}

$con = new mysqli($db_host, $db_user, $db_pass, $db_name);
if ($con->connect_error)
{
    die('Connect Error (' . $con->connect_errno . ') ' . $con->connect_error);
}

$sql = "DELETE FROM mytable WHERE 'index' = " . $_GET['id'];
if (!$result = $con->prepare($sql))
{
    die('Query failed: (' . $con->errno . ') ' . $con->error);
}

if (!$result->bind_param('i', $_GET['ID']))
{
    die('Binding parameters failed: (' . $result->errno . ') ' . $result->error);
}

if (!$result->execute())
{
    die('Execute failed: (' . $result->errno . ') ' . $result->error);
}

if ($result->affected_rows > 0)
{
    echo "The ID was deleted with success.";
}
else
{
    echo "Couldn't delete the index.";
}
$result->close();
$con->close();

它必须是简单的东西，但我无法弄明白。

Answer 1

您在SQL中使用了错误的引号类型。要转义包含保留字的表或列名称，请使用反引号。如果您使用的是bind_param，则必须将?放入查询中，以替换参数。

$sql = "DELETE FROM mytable WHERE `index` = ?";

Answer 2

替换delete.php文件中的以下行：

$sql = "DELETE FROM mytable WHERE 'index' = " . $_GET['id'];

使用：

$sql = "DELETE FROM mytable WHERE `index` = ?";

建议的替换声明中的更改包括：

使用反引号替换列名index周围的单引号。请注意，MySQL转义字符是一个反引号而不是单引号。
您的delete查询中没有包含任何参数占位符，但是您正在尝试绑定整数参数。

从显示的表中删除行

2 个答案: