我正试图让我的手机的某个区域响应轻击手势。为此,我在我的单元格中添加了一个名为“touchViewProfile”的UIView。此代码已按原样添加到cellForRowAtIndexPath:
中- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
static NSString *simpleTableIdentifier = @"SimpleTableCell";
SimpleTableCell *cell = (SimpleTableCell *)[tableView dequeueReusableCellWithIdentifier:simpleTableIdentifier];
if (cell == nil)
{
NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"SimpleTableCell" owner:self options:nil];
cell = [nib objectAtIndex:1];
}
// Tag Gesture Recognizer for Profile
UITapGestureRecognizer *tapProfile = [[UITapGestureRecognizer alloc]
initWithTarget:self
action:@selector(showProfile)];
tapProfile.numberOfTapsRequired = 1;
tapProfile.numberOfTouchesRequired = 1;
cell.touchViewProfile.userInteractionEnabled = YES;
[cell.touchViewProfile addGestureRecognizer:tapProfile];
return cell;
}
它适用于除第一个细胞之外的每个细胞。我忘记了什么吗?我在.h
中声明了“UIGestureRecognizerDelegate”编辑:“touchViewProfile”是我在SimpleTableCell.xib中使用Interface Builder创建的UIView。这是一个以.m
合成的属性答案 0 :(得分:1)
您需要先获得单元格索引值,因此我们需要实现UI手势代理
-(void)showProfile:(UIGestureRecognization *)recognize{
if(recognize.state==UIGestureRecognizeStateEnded){
CGPoint touched=[recognize locationInVie:self.tableView];
NSIndexPath *touchIndex=[self.tableView indexPathForRowAtPoin:touched];
SimpleTableViewCell *touchedCell=[self.tableView cellForRowAtIndexPath:touchedIndex];
//your code
}
}