我有以下CountDownTimer
帮助我设置每490毫秒30秒长的按钮。
是否可以说前10秒“滴答”应该是1000毫秒,接下来的10秒是700毫秒,最后10秒是490毫秒?
new CountDownTimer(30000, 490) {
@Override
public void onTick(long millisUntilFinished) {
for(int i = 0; i< arr.size(); i++){
Button aga = arr.get(i);
if(aga.getVisibility() == View.VISIBLE){
aga.setVisibility(View.GONE);
}
}
int zufall = (int) (Math.random()*23);
setNextButton(arr.get(zufall));
}
答案 0 :(得分:0)
Timer mTimer; // Global
public void countDownTimerCaller()
{
static int count = 0;
int time;
switch(count)
{
case 0:
time = 1000;
break;
case 1:
time = 700;
break;
case 2:
time = 490;
break;
default:
mTimer.cancel(); // stop timer
return;
}
new CountDownTimer(10000, time) {
@Override
public void onTick(long millisUntilFinished) {
for(int i = 0; i< arr.size(); i++){
Button aga = arr.get(i);
if(aga.getVisibility() == View.VISIBLE){
aga.setVisibility(View.GONE);
}
}
int zufall = (int) (Math.random()*23);
setNextButton(arr.get(zufall));
}
}
count++;
}
mTimer = new Timer().schedule(countDownTimerCaller, 10000); // call from where ever you created CountDownTimer instance
答案 1 :(得分:0)
除了按照这些间隔启动新的计时器来处理新的要求之外,最好的办法就是找到一个公约数,然后将其设置为你的间隔,然后使用一个带模数的开关按照你想要的时间行事。
答案 2 :(得分:0)
希望这会有所帮助。
public void countDown(long time) {
if (time == 490) {
return;
}
new CountDownTimer(10000, time) {
public void onTick(long millisUntilFinished) {
// Do whatever you want
}
public void onFinish() {
countDown(nextTime); // nextTime can be 700, 100, ... It's up to you. (Your rule). :">
}
}.start();
}