Java Servlet多文件上载变体

时间:2014-01-25 07:51:31

标签: java servlets file-upload

有人可以帮我提出一个可以上传这种变体文件的Java Servlet,或者让我知道如何:

5个文件输入类型字段,但只填写其中的1个或2个(在任何文件字段中),并上传那些没有。文件。

我发现了问题:

1)如果我填写的文件字段不是第一个,那么它就不会上传我的文件。 例如我填写第3个文件字段,然后单击上传。该文件将不会上传。但如果我填写第一个,它将被上传。如果我填写任何2-3个字段,但如果我没有按顺序填写它们(1,2,3 ......),它们将不会被上传。

2)我在文件字段下面有单选按钮。如果我没有填写所有文件字段,servlet将不会读取单选按钮值。有人可以告诉我为什么会这样吗?

总之,当且仅当我填写所有5个文件字段并勾选其中一个单选按钮时,它才有效。

HTML代码:

<html>
<head>
<title>File Uploading Form</title>
</head>
<body>
<h3>Energy Efficient Color Mapping Texture Transformer</h3>
Select 5 images to upload: <br />
<form action="UploadServlet" method="post"
                    enctype="multipart/form-data">
<b>Image 1</b>                  
<input type="file" name="file1" size="50" />
<br />
<b>Image 2</b>
<input type="file" name="file2" size="50" />
<br />
<b>Image 3</b>
<input type="file" name="file3" size="50" />
<br />
<b>Image 4</b>
<input type="file" name="file4" size="50" />
<br />
<b>Image 5</b>
<input type="file" name="file5" size="50" />
<br /><br />
Select conversion scheme below: <br />
<input type="radio" name="scheme" value="1" /> Sat 25 Hue 9 <br />
<input type="radio" name="scheme" value="2" /> Sat 25 Hue 24 <br />
<input type="radio" name="scheme" value="3" /> Sat 25 Hue 36 <br />
<input type="radio" name="scheme" value="4" /> Sat 50 Hue 9 <br />
<input type="radio" name="scheme" value="5" /> Sat 70 Hue 9 <br />
<input type="radio" name="scheme" value="6" /> Sat 50 Hue 24 <br />
<input type="radio" name="scheme" value="7" /> Sat 70 Hue 36
<br /><br />
<input type="submit" value="Upload File" />
</form>
</body>
</html>

所以说,我想填写图片3和4,并上传这2张图片。 servlet:

// Import required java libraries
import java.io.*;
import java.util.*;

import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.io.output.*;

public class UploadServlet extends HttpServlet {

private boolean isMultipart;
private String filePath;
private int maxFileSize = 5*1024*1024;
private int maxMemSize = 4 * 1024*1024;
private File file ;

public void init( ){

}
public void doPost(HttpServletRequest request, 
           HttpServletResponse response)
          throws ServletException, java.io.IOException {
  // Check that we have a file upload request
  isMultipart = ServletFileUpload.isMultipartContent(request);
  response.setContentType("text/html");
  java.io.PrintWriter out = response.getWriter( );
  if( !isMultipart ){
     out.println("<html>");
     out.println("<head>");
     out.println("<title>Servlet upload</title>");  
     out.println("</head>");
     out.println("<body>");
     out.println("<p>No file uploaded</p>"); 
     out.println("</body>");
     out.println("</html>");
     return;
  }
  DiskFileItemFactory factory = new DiskFileItemFactory();
  // maximum size that will be stored in memory
  factory.setSizeThreshold(maxMemSize);
  // Location to save data that is larger than maxMemSize.
  factory.setRepository(new File("c:\\temp"));

  // Create a new file upload handler
  ServletFileUpload upload = new ServletFileUpload(factory);
  // maximum file size to be uploaded.
  upload.setSizeMax( maxFileSize );

  try{ 
  // Parse the request to get file items.
  List fileItems = upload.parseRequest(request);

  // Process the uploaded file items
  Iterator i = fileItems.iterator();

  out.println("<html>");
  out.println("<head>");
  out.println("<title>Servlet upload</title>");  
  out.println("</head>");
  out.println("<body>");

  // Get the file location where it would be stored.
  filePath = 
         getServletContext().getInitParameter("file-upload");

  //Create calendar for folder naming purpose
  GregorianCalendar gcalendar = new GregorianCalendar();
  String date=String.valueOf(gcalendar.get(Calendar.DATE));
  String month=String.valueOf(gcalendar.get(Calendar.MONTH)+1);
  String year=String.valueOf(gcalendar.get(Calendar.YEAR));
  String hour=String.valueOf(gcalendar.get(Calendar.HOUR));
  String minute=String.valueOf(gcalendar.get(Calendar.MINUTE));
  String second=String.valueOf(gcalendar.get(Calendar.SECOND));

  //create a new filepath
  filePath= filePath + date+"-"+month+"-"+year+"_"+hour+minute+second;

  boolean newfolder= (new File(filePath)).mkdirs();

  if (newfolder){
    System.out.println("Created new folder");
  }

  while ( i.hasNext () ) 
  {
     FileItem fi = (FileItem)i.next();
     if ( fi.isFormField() )
     {
        out.println("is a form field <br>");
        String fieldName = fi.getFieldName();
        String fieldValue = fi.getString();
        out.println(fieldName+": "+fieldValue);
     }
     else
     //if ( !fi.isFormField () )    
     {
        // Get the uploaded file parameters
        String fieldName = fi.getFieldName();
        String fileName = fi.getName();
        String contentType = fi.getContentType();
        boolean isInMemory = fi.isInMemory();
        long sizeInBytes = fi.getSize();
        // Write the file
        if( fileName.lastIndexOf("\\") >= 0 ){
           file = new File( filePath + "\\" +
           fileName.substring( fileName.lastIndexOf("\\"))) ;
        }else{
           file = new File( filePath + "\\" +
           fileName.substring(fileName.lastIndexOf("\\")+1)) ;
        }
        fi.write( file ) ;
        out.println("Uploaded Filename: " + fileName + "<br>");
     } 
  }
  out.println("</body>");
  out.println("</html>");
  }catch(Exception ex) {
   System.out.println(ex);
  }
  }
  public void doGet(HttpServletRequest request, 
                   HttpServletResponse response)
    throws ServletException, java.io.IOException {

    throw new ServletException("GET method used with " +
            getClass( ).getName( )+": POST method required.");
  } 
}

到目前为止,当我使用java servlet搜索多个文件上传时,我没有看到任何不同的变体。

1 个答案:

答案 0 :(得分:0)

好的,所以当任何文件字段为空时会出现此问题。这意味着fileName也是一个空字符串。解决此问题的一种方法是添加条件以跳过空文件:

if( fileName.equals("")){
continue;
}