Question

我正在使用django 1.6和python 2.7.2编写一个简单的django应用程序，我想快速创建一个Post对象，这样我就可以测试我写的其他内容了。使用内置的django Admin页面添加对象，它引发了一个错误'int' object is not subscriptable。我确信如果有必要，我可以用另一种方式创建对象，但我想知道这是否是我正在做的错误，我应该修复或如果它是一个我不应该担心的错误。

Models.py：

from django.db import models
from django.contrib.auth.models import User

class Forum(models.Model):
    name = models.CharField(max_length = 100)
    club = models.ForeignKey(Club, blank = True)
    public = models.BooleanField()

    def __unicode__(self):
        return self.name

class Thread(models.Model):
    name = models.CharField(max_length = 100)
    forum = models.ForeignKey(Forum)
    can_post = models.BooleanField()

    def __unicode__(self):
        return self.name

class Like(models.Model):
    user = models.ForeignKey(User)

    def __unicode__(self):
         return self.id

class Post(models.Model):
    body = models.TextField()
    poster = models.ForeignKey(User)
    thread = models.ForeignKey(Thread)
    forum = models.ForeignKey(Forum)
    likes = models.ManyToManyField(Like, blank = True)
    date_posted = models.DateTimeField(auto_now_add=True) 


    def __unicode__(self):
        return self.id

回溯：

File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/core/handlers/base.py" in get_response
  114.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/contrib/admin/options.py" in wrapper
  430.                 return self.admin_site.admin_view(view)(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/utils/decorators.py" in _wrapped_view
  99.                     response = view_func(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/views/decorators/cache.py" in _wrapped_view_func
  52.         response = view_func(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/contrib/admin/sites.py" in inner
  198.             return view(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/utils/decorators.py" in _wrapper
  29.             return bound_func(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/utils/decorators.py" in _wrapped_view
  99.                     response = view_func(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/utils/decorators.py" in bound_func
  25.                 return func(self, *args2, **kwargs2)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/db/transaction.py" in inner
  339.                 return func(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/contrib/admin/options.py" in add_view
  1131.                 self.log_addition(request, new_object)
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/contrib/admin/options.py" in log_addition
  598.             action_flag=ADDITION
File "/usr/local/lib/python2.7/dist-packages/Django-1.6-py2.7.egg/django/contrib/admin/models.py" in log_action
  19.         e = self.model(None, None, user_id, content_type_id, smart_text(object_id), object_repr[:200], action_flag, change_message)

Exception Type: TypeError at /admin/forums/post/add/
Exception Value: 'int' object is not subscriptable

Answer 1

尝试返回：

def __unicode__(self):
        return u"%s" % self.id

而不是

def __unicode__(self):
        return self.id

中的

Python希望你返回一个unicode字符串，但是你在这里返回一个int。

您也可以返回unicode(self.id)

Django内置管理员引发“int object is not subscriptable”添加对象时出错

1 个答案: