我正在试图弄清楚如何获得字符串中每个项目的数量。例如:
{"harley": ["apple", "apple", "banana"]}
那我怎么能得到这个:
Harley has Apple x 2 and Banana x 1
答案 0 :(得分:2)
from collections import Counter
d = {"harley": ["apple", "apple", "banana"]}
for k,v in d.items():
print("%s has %s" %(k, ', '.join("%s x %s"%(k,v) for k,v in Counter(v).items())))
答案 1 :(得分:2)
d = {"harley": ["apple", "apple", "banana"]}
from collections import Counter
for k,v in d.iteritems():
print k + ' has ' + ' and '.join('{0} x {1}'.format(name, count) for name, count in Counter(v).iteritems())