我有df1和df2以及sql join:
df1 <- data.frame(fn1 = c('','NA','' ,'BF'),
ln1 = c('DRFA', 'DEFF','DDFF', 'ANCD'))
df2 <- data.frame(fn2 = c('','AA','BB', 'BF'),
ln2 = c('DRFA', 'DEFF','FFFF', 'ANCD'))
library(sqldf)
nm = sqldf("
select a.*, b.*,
(a.fn1 !=' ' and a.fn1 == b.fn2 ) as fnm,
(a.ln1 == b.ln2) as lnm
from df1 a, df2 b
where (fnm + lnm)>= 1
")
> nm
fn1 ln1 fn2 ln2 fnm lnm
1 DRFA DRFA 1 1
2 NA DEFF AA DEFF 0 1
3 DDFF DRFA 1 0
4 BF ANCD BF ANCD 1 1
结果应该是1和3中的fnm应为0.如何纠正? 感谢
答案 0 :(得分:1)
您检查了a.fn1 != ' '
,其结果为T
的1和3,因为值为''
而不是' '
。试试a.fn1 != ''