Question

我正在尝试过滤django admin内联中的foreignkey字段中显示的选项。因此，我想访问正在编辑的父对象。我一直在研究，但找不到任何解决方案。

class ProjectGroupMembershipInline(admin.StackedInline):
    model = ProjectGroupMembership
    extra = 1
    formset = ProjectGroupMembershipInlineFormSet
    form = ProjectGroupMembershipInlineForm

    def formfield_for_foreignkey(self, db_field, request=None, **kwargs):
        if db_field.name == 'group':
            kwargs['queryset'] = Group.objects.filter(some_filtering_here=object_being_edited)
        return super(ProjectGroupMembershipInline, self).formfield_for_foreignkey(db_field, request, **kwargs)

我已经确认编辑对象时kwargs是空的，所以我无法从那里获取对象。

请帮忙吗？感谢

Answer 1

另一种方式，恕我直言，感觉比较干净，但与@ erichonkanen类似，答案是这样的：

class ProjectGroupMembershipInline(admin.StackedInline):
    # irrelevant bits....

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if db_field.name == "group":
            try:
                parent_obj_id = request.resolver_match.args[0]
                kwargs["queryset"] = Group.objects.filter(some_filtering_here=parent_obj_id)
            except IndexError:
                pass
        return super(
            ProjectGroupMembershipInline, self).formfield_for_foreignkey(db_field, request, **kwargs)

Answer 2

要过滤管理内联中可用于外键字段的选项，我会覆盖该表单，以便我可以更新表单字段的queryset属性。这样您就可以访问self.instance，这是表单中正在编辑的对象。所以像这样：

class ProjectGroupMembershipInlineForm(forms.ModelForm):
    def __init__(self, *args, **kwargs):
        super(ProjectGroupMembershipInlineForm, self).__init__(*args, **kwargs)
        self.fields['group'].queryset = Group.objects.filter(some_filtering_here=self.instance)

如果您执行上述操作，则无需使用formfield_for_foreignkey，它应该完成您所描述的内容。

Answer 3

我能够通过使用formfield_for_foreignkey并从url中剥离对象ID来解决它。这不是获取ID的最性感方式，但Django还没有提供对admin对象上对象ID的访问权限（它应该）。

class ObjectAdmin(admin.ModelAdmin):

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        obj_id = request.META['PATH_INFO'].rstrip('/').split('/')[-1]
        if db_field.name == 'my_field' and obj_id.isdigit():
            obj = self.get_object(request, obj_id)
            if obj:
                kwargs['queryset'] = models.Object.objects.filter(field=obj)
        return super().formfield_for_foreignkey(db_field, request, **kwargs)

Answer 4

@mkoistinen提供的答案很好，但django将父代ID存储在kwargs中而不是args中，因此像这样提取它是正确的。

parent_id = request.resolver_match.kwargs.get('object_id')

Answer 5

这是我想出的解决方案，看起来很干净

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if db_field.name == "group":
            parent_id = request.resolver_match.kwargs['object_id']
            kwargs["queryset"] = Group.objects.filter(some_column=parent_id)
        return super().formfield_for_foreignkey(db_field, request, **kwargs)

django admin inlines：从formfield_for_foreignkey获取对象

5 个答案: