Question

我将此作为bash脚本的一部分

{
    read -n1 -p "Do you want to download some tv programmes? [y/n/q] " ynq ;
    [Yy] read -n200 -p "Please input the tv programme numbers to download " 'tvbox';
        echo; cd /media/$USER/back2/proggies/; /usr/bin/get-iplayer --get $tvbox;
    [Nn]* ) echo;;     # moves on to next question in the script
    [Qq]* ) echo; exit;;            # quits
    * ) echo "Thank you ";;
    esac
};

但由于语法错误，它无法正常工作。我怎么能让它问两个问题，第二个问题只出现在第一个回答“y”时出现，然后语法错误被解决，以便脚本可以正常工作？感谢。

Answer 1

case声明的开头似乎格式不正确。

{
    read -n1 -p "Do you want to download some tv programmes? [y/n/q] " ynq
    case $ynq in
     [Yy]) read -n200 -p "Please input the tv programme numbers to download " 'tvbox'
           echo
           cd /media/$USER/back2/proggies/
           /usr/bin/get-iplayer --get $tvbox
           ;; 
     [Nn]* ) echo;;     # moves on to next question in the script
     [Qq]* ) echo; exit;;            # quits
         * ) echo "Thank you ";;
    esac
};

两个问题，第二个只出现在你回答'y'

1 个答案: