用str_replace替换url查询字符串

Question

我有一些网址，如下面的网址：

  

https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs？的 Q = 1280wq

     

https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs？的 Q = 5080wq

     

https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs？的 Q = 860

     

https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs？的 Q = 86058

现在我想用{58}之类的常量值替换q值，如何在PHP中使用str_replace进行此操作？

Answer 1

尝试这种方式：

$content = "https://mysite.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs?q=1280wq"; 

$content = preg_replace("q=\w+", "", $content); 

Answer 2

$url = 'https://mysite.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs?q=1280wq';

$query = parse_url($url, PHP_URL_QUERY);
parse_str($query);

echo $q;

Answer 3

可以通过这样的str_replace来完成：

<?php
$myString = 'https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs?q=1280wq';
$myNewString = str_replace('?q=', '/589/', $myString); //this line replaces the '?q=' with '/589/'
echo $myNewString; //OUTPUT: https://example.com/xyz/jjJAjsjahjsjhUAUiOAkskpAs/589/1280wq
?>