Question

我正在调用来自同一域名的网址列表，并为几千个域名返回他们的html片段，但是这个错误大约有1000行左右。

我能做些什么来避免这个错误吗？
在每一行之后创建一个等待步骤是否有意义？每隔几百行？

有没有更好的方法来解决这个问题？

  File "/Users.../ap.py", line 144, in <module> simpleProg()
  File "/Users.../ap.py", line 21, in simpleProg()
  File "/Users.../ap.py", line 57, in first_step()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
    response = self._open(req, data)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 418, in _open 
    '_open', req)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 1207, in http_open
    return self.do_open(httplib.HTTPConnection, req)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 1180, in do_open
    r = h.getresponse(buffering=True)
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 1030, in getresponse
    response.begin()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 407, in begin
    version, status, reason = self._read_status()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/httplib.py", line 365, in _read_status
    line = self.fp.readline()
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/socket.py", line 447, in readline
    data = self._sock.recv(self._rbufsize)
    socket.error: [Errno 54] Connection reset by peer

Python：Urllib2 | [Errno 54]由同行重置连接

0 个答案: