Android XMLPullParser：无法解析Html页面

Question

Android XMLPullParser无法解析具有javaScript函数的Html String，其中使用小于符号作为if条件。 还有其他任何建议......！

        String webContent = "........";
        XmlPullParserFactory xmlFactoryObject = XmlPullParserFactory.newInstance();
        XmlPullParser myParser = xmlFactoryObject.newPullParser();

        InputStream is = new ByteArrayInputStream( webContent.getBytes( "utf-8" ) );
        myParser.setInput(is, null);

        int event = myParser.getEventType();
        String tableData = "";
        while (event != XmlPullParser.END_DOCUMENT) 
        {
            String name=myParser.getName();
            Log.e(TAG, "The event name is : "+name);
            switch (event){
            case XmlPullParser.START_TAG:
                if(name.equals("table")){
                    tableData = myParser.getText();
                }
                break;
            case XmlPullParser.END_TAG:
                break;
            }        
            Log.e(TAG, "the text for tag "+name+"  is "+myParser.getText());

            event = myParser.next();

        }

当它试图解析脚本标记的以下字符串时，myparser.getText（）将文本返回到'＆lt;'如果条件符号但不符合脚本的结束标记

        <script type="text/javascript">
            jQuery(document).ready(function($) {
                var txt = $("p#crt").html().replace((/[A-Za-z]|(\W)/g),"")
                if(txt < 1) {txt = 0};
                $("#crtnumber").html(txt)
                if( txt == 1 ) {$("#crttext").html(" item")}
                else {$("#crttext").html(" items")}
                $("p#crt").remove()
            });
        </script>