为什么SQLAlchemy不能创建串行列?

时间:2014-01-24 09:10:21

标签: python sql postgresql sqlalchemy

SQLAlchemy正在为postgresql中的列生成序列,但不启用它们。我怀疑我可能在引擎设置方面做错了。

使用SQLAlchemy教程(http://docs.sqlalchemy.org/en/rel_0_9/orm/tutorial.html)中的示例:

#!/usr/bin/env python

from sqlalchemy import create_engine, Column, Integer, String, Sequence
from sqlalchemy.ext.declarative import declarative_base

Base = declarative_base()
class User(Base):
    __tablename__ = 'users'
    id = Column(Integer, Sequence('user_id_seq'), primary_key=True)
    name = Column(String(50))
    fullname = Column(String(50))
    password = Column(String(12))

    def __repr__(self):
        return "<User(name='%s', fullname='%s', password='%s')>" % (
                                self.name, self.fullname, self.password)

db_url = 'postgresql://localhost/serial'
engine = create_engine(db_url, echo=True)
Base.metadata.create_all(engine)

使用此脚本,将生成以下表格:

serial=# \d+ users
                                 Table "public.users"
  Column  |         Type          | Modifiers | Storage  | Stats target | Description 
----------+-----------------------+-----------+----------+--------------+-------------
 id       | integer               | not null  | plain    |              | 
 name     | character varying(50) |           | extended |              | 
 fullname | character varying(50) |           | extended |              | 
 password | character varying(12) |           | extended |              | 
Indexes:
    "users_pkey" PRIMARY KEY, btree (id)
Has OIDs: no

然而, 创建了序列:

serial=# select sequence_schema,sequence_name,data_type from information_schema.sequences ;
 sequence_schema | sequence_name | data_type 
-----------------+---------------+-----------
 public          | user_id_seq   | bigint

SQLAlchemy 0.9.1,Python 2.7.5 +,Postgresql 9.3.1,Ubuntu 13.10

-Reece

4 个答案:

答案 0 :(得分:17)

这是因为您为其提供了明确的Sequence。 postgresql中的SERIAL数据类型生成自己的序列,SQLAlchemy知道如何定位 - 所以如果省略Sequence,SQLAlchemy将呈现SERIAL,假设意图是该列是自动递增的(由autoincrement参数与Integer primary_key一起确定;它默认为True)。但是当传递Sequence时,SQLAlchemy会看到您不希望由SERIAL隐式创建的序列的意图,而是您要指定的序列:

from sqlalchemy import create_engine, Column, Integer, String, Sequence
from sqlalchemy.ext.declarative import declarative_base

Base = declarative_base()

class T1(Base):
    __tablename__ = 't1'

    # emits CREATE SEQUENCE + INTEGER
    id = Column(Integer, Sequence('user_id_seq'), primary_key=True)

class T2(Base):
    __tablename__ = 't2'

    # emits SERIAL
    id = Column(Integer, primary_key=True)

class T3(Base):
    __tablename__ = 't3'

    # emits INTEGER
    id = Column(Integer, autoincrement=False, primary_key=True)

engine = create_engine("postgresql://scott:tiger@localhost/test", echo=True)
Base.metadata.create_all(engine)

输出:

CREATE SEQUENCE user_id_seq

CREATE TABLE t1 (
    id INTEGER NOT NULL, 
    PRIMARY KEY (id)
)


CREATE TABLE t2 (
    id SERIAL NOT NULL, 
    PRIMARY KEY (id)
)


CREATE TABLE t3 (
    id INTEGER NOT NULL, 
    PRIMARY KEY (id)
)

答案 1 :(得分:1)

如果由于某种原因需要显式创建序列,例如设置起始值,并且仍然需要与使用Column(Integer, primary_key=True)表示法时相同的默认值行为,则可以使用以下代码完成:< / p>

#!/usr/bin/env python

from sqlalchemy import create_engine, Column, Integer, String, Sequence
from sqlalchemy.ext.declarative import declarative_base

Base = declarative_base()
USER_ID_SEQ = Sequence('user_id_seq')  # define sequence explicitly
class User(Base):
    __tablename__ = 'users'
    # use sequence in column definition, and pass .next_value() as server_default
    id = Column(Integer, USER_ID_SEQ, primary_key=True, server_default=USER_ID_SEQ.next_value())
    name = Column(String(50))
    fullname = Column(String(50))
    password = Column(String(12))

    def __repr__(self):
        return "<User(name='%s', fullname='%s', password='%s')>" % (
                                self.name, self.fullname, self.password)

db_url = 'postgresql://localhost/serial'
engine = create_engine(db_url, echo=True)
Base.metadata.create_all(engine)

答案 2 :(得分:0)

里斯

我还将该教程用作模型,并且无法使其与已存在的任何Postgres表一起使用,并且具有带序列序列的密钥ID列以生成新的密钥ID值。

像大卫一样,我发现序列必须与班级分开定义。对于任何使用“db.Model”方法的人来说,这是一个例子。

from flask.ext.sqlalchemy import SQLAlchemy
from sqlalchemy import Sequence
db = SQLAlchemy()

pageimpression_imp_id_seq = Sequence('pageimpression_imp_id_seq')
class PageImpression(db.Model):
        __tablename__ = 'pageimpression'
        imp_id = db.Column(db.Integer,     
    pageimpression_imp_id_seq,           
    server_default=usersession_sessionid_seq.next_value(),primary_key=True)
    logdate = db.Column(db.DateTime)
    sessionid = db.Column(db.String)
    path = db.Column(db.String)
    referrer = db.Column(db.String)

def __init__(self, imp_id, logdate, sessionid, path, referrer):
    self.imp_id = imp_id
    self.logdate = logdate
    self.sessionid = sessionid
    self.path = path
    self.referrer = referrer

def __repr__(self):
   return "<PageImpression(imp_id='%s', logdate='%s',sessionid='%s', path='%s', referrer='%s')>" % (self.imp_id, self.logdate, self.sessionid, self.path, self.referrer)

def PageImpressionAdd(sessionid):
    sessionid = 0 # dummy value for unit testing
    current_time = datetime.now().isoformat()
    if CurrentConfig.IMPRESSION_LOGGING_ON == True:     
        path = request.path
        if request.environ.get('HTTP_REFERER') and not request.environ.get('HTTP_REFERER').isspace():
            referrer = request.environ.get('HTTP_REFERER') # the string is not-empty
        else:
            referrer = '' # the string is empty
        from website.models import PageImpression
        thisPageImpression = PageImpression(None,current_time,sessionid, path, referrer)
        db.session.add(thisPageImpression)
        db.session.commit()
        # get the values created by the Postgres table defaults
        imp_id = thisPageImpression.imp_id
        logdate = thisPageImpression.logdate
    return current_time

答案 3 :(得分:0)

您也可以在没有任何 SQL 脚本的情况下通过 GUI pgAdmin 更改序列,如下所示:

选择您的数据库 -> 架构 -> 公共 -> 序列 -> 右键单击​​ -> 属性 -> 定义 -> 当前值。