Question

我有一个leave_applications表和一个employees表。当员工申请与leave_applications表一起存储的休假以及员工ID。当员工下次登录时，我正在显示他迄今已申请的休假申请。但问题是所有休假申请都在展示（即使是其他员工），但情况并非如此。那么如何限制只有登录的员工看到他的请假申请？我的LeaveApplicationsController.php页面显示了叶子：

public function index()
    {
        $this->LeaveApplication->recursive = 0;
        $leavereqs = $this->set('leaveApplications', $this->Paginator->paginate());
        //return $this->LeaveApplication->Employee->find('all', array('conditions' => array('LeaveApplications.employee_id'=>$this->Auth->user('id'))));
        return $this->LeaveApplication->find('all');
        //echo $log_user_id = $this->Auth->user('role'); die();
        //return $this->LeaveApplication->Employee->query("SELECT * FROM leave_applications WHERE employee_id = '$log_user_id'");
        //return $this->LeaveApplication->Employee->query("SELECT la.leave_type, la.subject, la.detail, la.from_date, la.to_date, la.applied_on, la.leave_status, la.leave_status_date FROM leave_applications la INNER JOIN employees e ON la.employee_id = e.id INNER JOIN users u ON e.user_id = u.id WHERE la.employee_id = '$log_user_id'");
    }

请注意，我在LeaveApplicationsController.php中的代码不在EmployeesController.php中，因为当员工点击所有叶子按钮/链接时，将调用此控制器的索引视图。注释代码是我尝试过的，但它们都没有工作。

Answer 1

确保Auth的员工ID正常。

查询离职表，其中employee_is是登录用户

$employeeId = $this->Auth->user('id');
return $this->LeaveApplication->findAllByEmployeeId($employeeId);

Answer 2

索引函数必须类似于：

public function index()
        {   
            $id = "GET EMPLOYEE ID FROM SESSION OR BY PASSING ARGUMENT";
            $this->LeaveApplication->recursive = 0;
            $conditions = array("employee.id" => "$id");
            $leavereqs = $this->set('leaveApplications', 
                           $this->Paginator->paginate('MODEL NAME', $conditions)
                          );

        }

Answer 3

要获取已登录Employee的应用程序，您应在find函数中指定Employee_id：

public function index(){

  //Make sure the Employee is logged in
  $id = $this->Auth->user('id');
  if($id){

     // get leave applications of logged in Employee
     $leavereqs = $this->LeaveApplication->find('all', array(
         'conditions'=> array('Employee_id'=>$id)
    ));

    $this->set('leavereqs',$leavreqs');
  }
}

如果它不起作用，请调试$ this-＆gt; Auth-＆gt; user（），并确保在数据库中指定Employee_id离开应用程序。

Answer 4

您可以使用这样的魔术查找类型：

findAllByEmployeeId($emp_id)

仅在数据库中的字段名称为employee_id时才会出现。另一种获取数据的方法是：

find('all',array('conditions' => array('employee_id' => $emp_id));

仅查看CakePHP中的登录用户数据

4 个答案: