I have a document structure that looks similar to this:
<article id="post1" class="post-5 page type-page" >
<section class = "holder clearfix">
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
</a>
</div>
</section>
</article>
我想要做的是使用JQuery为每个 a 元素添加一个带有类和唯一ID的div。
最终结果看起来像这样
<article id="post1" class="post-5 page type-page" >
<section class = "holder clearfix">
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
<div id="button1" class = "shiny-button"> </div> // unique ID
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
<div id="button2" class = "shiny-button"> </div> // unique ID
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
<div id="button3" class = "shiny-button"> </div> // unique ID
</a>
</div>
<div class = "four columns">
<a title class = "single-image short-link" href "http://whatever.com" target = "self">
<div id="button4" class = "shiny-button"> </div> // unique ID
</a>
</div>
</section>
</article>
到目前为止,以下JQuery代码让我大约一半:
$('<div/>', {
class:'shiny-button',
}).appendTo('.single-image');
我尝试使用类似于以下内容的代码,但我似乎无法正确使用
$('<div/>', {
class:'shiny-button',
id: 'button1',
}).appendTo('.holder .four:nth-child(1)');
谢谢。
答案 0 :(得分:0)
尝试使用每个。所以
$('.single-image').each(function(index){
//Append new element to $(this)
//index will be a counter
//$(this) = the current $('.single-image') element
});
我相信你可以使用索引是唯一的。我记不住了,但jQuery中记录了.each()
函数。
答案 1 :(得分:0)
尝试
$('#post1 .single-image').append(function(i){
return '<div id="button'+(i+1)+'" class = "shiny-button"> dd</div>'
})
演示:Fiddle