我正在写一小段PHP代码,它会显示一个表格; X轴将显示最近14天的窗口,Y轴将显示第一列中的计算机列表,每个日期单元格的内容将显示该日期的计算机状态(示例如下)。
|Hostname |1 |2 |3 |
+-----------+----+---------+
|computer1 |OK |DEAD |OK |
|computer2 |OK | | |
我需要表格完全动态 - 所以如果今天添加新系统;它将显示并拥有今天的状态,但不是前一天。到目前为止一切都那么好 - 但是我的桌子没有正确关闭 - 所以计算机状态是垂直添加而不是水平添加,所以它看起来更像是这样:
|Hostname |1 |2 |3 |
+-----------+----+---------+
|computer1 |OK | | |
|computer2 |OK | | |
|computer1 |DEAD| | |
|computer1 |OK | | |
无法找到关闭桌子的好方法,同时保持准确,动态的内容。该表的代码包含在下面(这是缺少主机名列btw):
<?php
$dates2 = mysql_query("SELECT day, month, year, hostname FROM log WHERE date >= DATE_ADD(CURDATE(), INTERVAL -14 DAY) ORDER BY date;");
?>
<?php
echo "</thead>";
echo "<tbody>";
echo "<tr>";
while ($row = mysql_fetch_array($dates2))
{
echo "<td><a href='/log/" . $row['hostname'] . ".log'>" . $row['hostname'] . "</a></td>";
$state_date = mysql_query("SELECT state FROM log WHERE hostname = '" . $row['hostname'] . "' AND day = '" . $row['day'] . "' AND month = '" . $row['month'] . "' AND year = '" . $row['year'] . "' ORDER BY date;");
while($row2 = mysql_fetch_array($state_date))
{
if(isset($row2['state']))
{
if ($row2['state'] == 'ok')
{
echo "<td bgcolor='#FF0000'>" . $row2['state'] . "</td>";
}
elseif($row2['state'] == 'dead')
{
echo "<td bgcolor='#00FF00'>" . $row2['state'] . "</td>";
}
else
{
echo "<td bgcolor='#FFD732'>" . $row2['state'] . "</td>";
}
}
else
{
echo "<td>Unknown</td>";
}
}
echo "</tr>";
}
echo "</tbody></table>";
mysql_close($con);
?>
答案 0 :(得分:2)
你需要把&lt; TR&gt;部分在循环内。 TR是排。你把所有东西放在一排。
while (...)
{
echo "<tr>";
...
echo "</tr>";
}
答案 1 :(得分:0)
您需要遍历主机:
$hostnames = mysql_query("SELECT DISTINCT hostname FROM log WHERE date >= DATE_ADD(CURDATE(), INTERVAL -14 DAY) ORDER BY date;");
while($hostname_row = mysql_fetch_array($hostnames))
{
$dates2 = mysql_query("SELECT day, month, year, hostname FROM log WHERE date >= DATE_ADD(CURDATE(), INTERVAL -14 DAY) AND hostname = '" . $hostname_row['hostname'] . "' ORDER BY date;");
echo "<tr>";
while ($row = mysql_fetch_array($dates2))
{
if(isset($row2['state']))
{
if ($row2['state'] == 'ok')
{
echo "<td bgcolor='#FF0000'>" . $row2['state'] . "</td>";
}
elseif($row2['state'] == 'dead')
{
echo "<td bgcolor='#00FF00'>" . $row2['state'] . "</td>";
}
else
{
echo "<td bgcolor='#FFD732'>" . $row2['state'] . "</td>";
}
}
else
{
echo "<td>Unknown</td>";
}
}
echo "</tr>";
}
答案 2 :(得分:0)
有你的问题: