RequestMappingHandler不映射Spring Security生成的`/ login`路径

Question

我认为这可能与我配置的这一部分有关：

<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <beans:property name="prefix" value="/WEB-INF/views/" />
    <beans:property name="suffix" value=".jsp" />
</beans:bean>

我在这里遵循了Spring Security Tutorial：http://docs.spring.io/spring-security/site/docs/3.2.x/guides/form.html。我无法导航到myApp / login，并且它没有显示在所有其他映射完成的日志中。

INFO : org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping - Mapped "{[/],methods=[GET],params=[],headers=[],consumes=[],produces=[],custom=[]}" onto public java.lang.String package.controller.HomeController.home(java.util.Locale,org.springframework.ui.Model)
INFO : org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping - Mapped "{[/officeSearchResults],methods=[POST],params=[],headers=[],consumes=[],produces=[],custom=[]}" onto public org.springframework.web.servlet.ModelAndView package.controller.OfficeController.search(java.lang.String)
...

我的代码和示例之间的唯一区别是我在.jsp中构建了我的视图，而不是百里香。这是jsp，但我不确定它是否重要：

    <form name="f" action="j_spring_security_check"
        method="post">
        <input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}"/>
        <table>
            <tr>
                <td>User:</td>
                <td><input type='text' name='j_username' value=''>
                </td>
            </tr>
            <tr>
                <td>Password:</td>
                <td><input type="password" name="j_password" />
                </td>
            </tr>
            </table>
            <input name="submit" type="submit"
                    value="submit" />
            <input name="reset" type="reset" />
    </form>

更新：

的web.xml：

  <context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:jpaContext.xml</param-value>
  </context-param>
  <listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
  </listener>
  <servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
      <param-name>contextConfigLocation</param-name>
      <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/</url-pattern>
  </servlet-mapping>
</web-app>

请提供建议或解决方案。感谢。