我只想从麦克风录制音频并将其保存在.wav文件中。 这是我的c#代码:
IsolatedStorageFileStream fileStream = new IsolatedStorageFileStream(Filename, FileMode.Create, myIsolatedStorage);
// Add wave header:
BinaryWriter bw = new BinaryWriter(fileStream);
bw.Write(new char[4] { 'R', 'I', 'F', 'F' });
bw.Write((int)fileStream.Length + 36);
bw.Write(new char[8] { 'W', 'A', 'V', 'E', 'f', 'm', 't', ' ' });
bw.Write((int)16);
bw.Write((short)1);
short channels = 2;
bw.Write(channels);
int samplerate = 8000;
bw.Write(samplerate);
short BitsPerSample = 8;
bw.Write((int)(samplerate * ((BitsPerSample * channels) / 8)));
bw.Write((short)((BitsPerSample * channels) / 8));
bw.Write(BitsPerSample);
bw.Write(new char[4] { 'd', 'a', 't', 'a' });
int DataLength = (int)fileStream.Length;
bw.Write(DataLength);
fileStream.Write(stream.GetBuffer(), 44, (int)stream.Position);
fileStream.Position = 0;
bw.Close();
fileStream.Close();
如果我用VLC打开.wav文件,它不会重现任何内容。 如果我以这种方式打开文件(见下文),就在我保存之后,它会正确地重现声音:
byte[] buffer = new byte[microphone.GetSampleSizeInBytes(duration)];
using (IsolatedStorageFile userStore = IsolatedStorageFile.GetUserStoreForApplication())
using (IsolatedStorageFileStream openfilestream = userStore.OpenFile(Filename, FileMode.Open))
{
openfilestream.Read(buffer, 0, buffer.Length);
}
SoundEffect sound = new SoundEffect(buffer, microphone.SampleRate, AudioChannels.Mono);
soundInstance = sound.CreateInstance();
soundIsPlaying = true;
soundInstance.Play();
我只是编辑上面的代码,因为Adriano说(但它不起作用):
IsolatedStorageFileStream fileStream = new IsolatedStorageFileStream(Filename, FileMode.Create, myIsolatedStorage);
fileStream.Write(stream.GetBuffer(), 44, (int)stream.Position);
// Aggiunta wav header:
BinaryWriter bw = new BinaryWriter(fileStream);
bw.Write(new char[4] { 'R', 'I', 'F', 'F' });
bw.Write((int)fileStream.Length - 8);
bw.Write(new char[8] { 'W', 'A', 'V', 'E', 'f', 'm', 't', ' ' });
bw.Write((int)16);
bw.Write((short)1);
short channels = 1;
bw.Write(channels);
int samplerate = 8000;
bw.Write(samplerate);
short BitsPerSample = 8;
bw.Write((int)(samplerate * ((BitsPerSample * channels) / 8)));
bw.Write((short)((BitsPerSample * channels) / 8));
bw.Write(BitsPerSample);
bw.Write(new char[4] { 'd', 'a', 't', 'a' });
int DataLength = (int)fileStream.Length - 44;
bw.Write(DataLength);
fileStream.Position = 0;
bw.Close();
fileStream.Close();
答案 0 :(得分:0)
这些行看起来很可疑:
bw.Write((int)fileStream.Length + 36);
// ...
int DataLength = (int)fileStream.Length;
// ...
short channels = 2;
// ...
int samplerate = 8000;
如果它是单声道,频道应该是1。
看起来像fileStream.length总是0,你刚刚在上面创建它,看起来你打算写的是实际wav数据的长度。 stream.length?
8K的采样率质量很差,但这可能就是你猜的那样。最好使用实际的麦克风属性来确定这一点。
此外,如果将0x52494646和0x57415645设置为几个常量而不是使用char数组,则可能更容易阅读。
The canonical WAVE format starts with the RIFF header:
0 4 ChunkID Contains the letters "RIFF" in ASCII form
(0x52494646 big-endian form).
4 4 ChunkSize 36 + SubChunk2Size, or more precisely:
4 + (8 + SubChunk1Size) + (8 + SubChunk2Size)
This is the size of the rest of the chunk
following this number. This is the size of the
entire file in bytes minus 8 bytes for the
two fields not included in this count:
ChunkID and ChunkSize.
8 4 Format Contains the letters "WAVE"
(0x57415645 big-endian form).
The "WAVE" format consists of two subchunks: "fmt " and "data":
The "fmt " subchunk describes the sound data's format:
12 4 Subchunk1ID Contains the letters "fmt "
(0x666d7420 big-endian form).
16 4 Subchunk1Size 16 for PCM. This is the size of the
rest of the Subchunk which follows this number.
20 2 AudioFormat PCM = 1 (i.e. Linear quantization)
Values other than 1 indicate some
form of compression.
22 2 NumChannels Mono = 1, Stereo = 2, etc.
24 4 SampleRate 8000, 44100, etc.
28 4 ByteRate == SampleRate * NumChannels * BitsPerSample/8
32 2 BlockAlign == NumChannels * BitsPerSample/8
The number of bytes for one sample including
all channels. I wonder what happens when
this number isn't an integer?
34 2 BitsPerSample 8 bits = 8, 16 bits = 16, etc.
2 ExtraParamSize if PCM, then doesn't exist
X ExtraParams space for extra parameters
The "data" subchunk contains the size of the data and the actual sound:
36 4 Subchunk2ID Contains the letters "data"
(0x64617461 big-endian form).
40 4 Subchunk2Size == NumSamples * NumChannels * BitsPerSample/8
This is the number of bytes in the data.
You can also think of this as the size
of the read of the subchunk following this
number.
44 * Data The actual sound data.
通过: