Question

我需要在同一个图中绘制两个直方图并且存在重叠。我使用像

这样的命令

plt.hist(data1,bins=40,normed=True,histtype='step')
plt.hist(data2,bins=40,normed=True,histtype='step')

为了区分这两个不同的直方图（需要以黑色和白色呈现它们），我想让其中一个以虚线而不是实线显示，所以我试过

plt.hist(data1,bins=40,normed=True,histtype='step',ls='--')

给了我以下错误消息：

Exception in Tkinter callback
Traceback (most recent call last):
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/tkinter/__init__.py", line 1475, in __call__
    return self.func(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/tkinter/__init__.py", line 534, in callit
    func(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/backends/backend_tkagg.py", line 363, in idle_draw
    self.draw()
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/backends/backend_tkagg.py", line 348, in draw
    FigureCanvasAgg.draw(self)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/backends/backend_agg.py", line 451, in draw
    self.figure.draw(self.renderer)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/artist.py", line 56, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/figure.py", line 1035, in draw
    func(*args)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/artist.py", line 56, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/axes.py", line 2088, in draw
    a.draw(renderer)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/artist.py", line 56, in draw_wrapper
    draw(artist, renderer, *args, **kwargs)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/patches.py", line 401, in draw
    gc.set_linestyle(self._linestyle)
  File "/opt/local/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/site-packages/matplotlib/backend_bases.py", line 962, in set_linestyle
    raise ValueError('Unrecognized linestyle: %s' % str(style))
ValueError: Unrecognized linestyle: --

我的问题是，如何更改线条样式（实线/虚线和颜色）？或者是否有另一种方法可以用期望的线条样式绘制这两个直方图？

Answer 1

您导入了所需的所有库吗？此外，有时并非所有的线条都适用于所有情节类型。例如，有些线条适用于不适用于矢量的图形（即使它们看起来应该如此）。如果符号名称不起作用' - '，最好尝试命名版本'dashed'。

您可以在绘图参数中提供线条样式（或颜色，宽度等）的元组，就像在example from the matplotlib docs linewidths上的plt.hist(data1,bins=40,normed=True,histtype='step',linestyle=('solid','dashed'))所做的那样（线宽为Ctrl + F）< / p>

使用plot命令，它应该如下所示：

color

您可以指定一个linestyle参数，就像plt.hist(data1,bins=40,normed=True,histtype='step',linestyle=('solid','dashed'),color=('black','k'))的完成方式一样。绘制线条时，pyplot会查看您提供的每个元组中的第一个项目。因此，如果你想要一条纯黑线和一条黄色虚线，它看起来像

{{1}}

因此'solid'应与'black'配对，'dashed'应与'k'配对。这应该适用于您要使用的任何其他行属性。

Answer 2

edgeColor 参数在我的系统上有效。

plot.hist (bins = 10, xlim = [0.0,1], ylim = [0.0,70], color = 'blue', edgeColor = 'black')

matplotlib中的直方图图形线条样式

2 个答案: