Question

这里我得到我的远程服务器响应（JSON）以在这种方法中转换为NSDictionary。

NSDictionary *dictionary = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];

NSLog (@"%@",dictionary);

我的输出文字如下：

输出：

{
            "city" = "";
            "state" = "";
            "zip" = "";
            "address" = 0;
            "id" = 1;
            "name" = "test name";
            "country_name" = 0;
            email = 0;
            "fax" = 0;
            "mobile" = 0;
            phone = 1234567890;
            website = "";
        }

如果我曾经从NSDictionary获取名称变量。我得到了这个预期

-[__NSCFArray objectForKey:]: unrecognized selector sent to instance 0xcada210

-(void)addAccountDatails:(NSDictionary *)accArray{

        NSLog(@"- %@",[accArray objectForKey:@"name"]);
    }

如何在NSDictionary中获取名称值

Answer 1

将NSDictionary更改为NSArray：

NSArray *array = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
[self addAccountDatails:array];

-(void)addAccountDatails:(NSArray *)accArray {    
    NSLog(@"- %@",[(NSDictionary*)accArray[0] objectForKey:@"name"]);
}

Answer 2

请试试这个

NSArray *array = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];

for(NSDictionary *dict in array)
{
    NSLog(@"Name = %@", [dict objectForKey:@"name"]);
}

如何从NSDictionary获取JSON值

2 个答案: