我有三个可跳转的标签。在第一个标签中,我有一个包含1000多个项目的列表视图。
我尝试使用Asynctask和Runnable填充列表,我对此没有任何问题。
问题是当我尝试将适配器分配给listview时。我注意到无论适配器中有多少项,无论它是1还是1000,当它尝试执行时:listView.setAdapter(适配器),它会跳过大约30帧......
由于listView.setAdapter(适配器)用于第一个选项卡,因此每当用户尝试进入该选项卡时,UI会冻结几毫秒。虽然这不是一个严重的问题,但我不喜欢它。
问题是:这是正常的,当我们调用listView.setAdapter(适配器)时,UI会冻结几毫秒并跳过一些帧吗?无论如何都没有解决这个问题?
我清楚吗?
Carpet_handler ch; // my db handler
ListView listview;
public ArrayList<CarpetGen> carpetGens;
CarpetAdapter adapter;
boolean loadingMore=false;
int offset;
Context ctx;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_first_page_customers, container, false);
ch=new Carpet_handler(getActivity()); // db handler
listview = (ListView) rootView.findViewById(R.id.listView2);
ctx=this.getActivity();
carpetGens = new ArrayList<CarpetGen>();
offset=0;
adapter = new CarpetAdapter(getActivity(), R.layout.row, carpetGens);
listview.setAdapter(adapter); // adapter is empty first time, runnable fills it
listview.setOnItemClickListener(myClickListener);
//Here is where the magic happens
listview.setOnScrollListener(new OnScrollListener(){
@Override
public void onScrollStateChanged(AbsListView view, int scrollState) {}
@Override
public void onScroll(AbsListView view, int firstVisibleItem,
int visibleItemCount, int totalItemCount) {
//what is the bottom iten that is visible
int lastInScreen = firstVisibleItem + visibleItemCount;
//is the bottom item visible & not loading more already ? Load more !
if((lastInScreen == totalItemCount) && !(loadingMore)){
Thread thread = new Thread(null, loadMoreListItems);
thread.start();
}
}
});
return rootView;
}
//Runnable to load the items
private Runnable loadMoreListItems = new Runnable() {
@Override
public void run() {
//Set flag so we cant load new items 2 at the same time
loadingMore = true;
//Reset the array that holds the new items
carpetGens= new ArrayList<CarpetGen>();
carpetGens.addAll(ch.getAllCustomerCarpets1(getActivity().getIntent().getIntExtra("recordid", -1), offset));
offset+=15;
//Done! now continue on the UI thread
if(getActivity()==ctx)
getActivity().runOnUiThread(returnRes);
}
};
//Since we cant update our UI from a thread this Runnable takes care of that!
private Runnable returnRes = new Runnable() {
@Override
public void run() {
//Loop thru the new items and add them to the adapter
if(carpetGens != null && carpetGens.size() > 0){
for(int i=0;i < carpetGens.size();i++)
adapter.add(carpetGens.get(i));
}
adapter.notifyDataSetChanged();
loadingMore = false;
}
};
这是我的适配器:
public class CarpetAdapter extends ArrayAdapter<CarpetGen> {
private final Context context;
private final int rowResourceId;
//private final String[] Ids;
private final ArrayList<CarpetGen> Objects;
public CarpetAdapter(Context context, int textViewResourceId, ArrayList<CarpetGen> objects){//Arr[] objects) {
super(context, textViewResourceId, objects);
// TODO Auto-generated constructor stub
this.context = context;
this.rowResourceId = textViewResourceId;
this.Objects = objects;
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder;
View rowView = convertView;
CarpetGen i = Objects.get(position);
if (rowView == null) {
LayoutInflater inflater = (LayoutInflater) context
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
rowView = inflater.inflate(R.layout.row, parent, false);
//TextView textView = (TextView) rowView.findViewById(R.id.textView);
//textView.setText(i.Result_String);
holder = new ViewHolder();
holder.title = (TextView) rowView
.findViewById(R.id.textView);
rowView.setTag(holder);
} else {
holder = (ViewHolder) rowView.getTag();
}
holder.title.setText(i.Result_String);
return rowView;
}
static class ViewHolder {
TextView title;
} }
答案 0 :(得分:1)
我认为这是完全正常的。请记住,它必须刷新布局,即使它没有元素,当你调用setAdapter()
方法时,你正在做一些取决于你的实现的操作,但基本上它不是0秒 - 奇迹。正如@laalto建议的那样,自定义适配器实现中也可能存在瓶颈,因此您可能需要考虑在Thread
(或基本上是AsyncThread
)中进行一些工作。但正如我所说,我不担心它(总的来说,如果在虚拟设备中发生这种跳帧)。
答案 1 :(得分:0)
我认为您应该尝试执行以下操作:
1st - 使用AsyncTask加载doInBakground方法中的项目。
2nd - doPostExecute方法中AsyncTask中的listView.setAdapter。
希望有所帮助