Question

我有以下时间：

2010-01-25 03:13:34.384 - GMT Time Zone
2010-01-25 11:13:34.384 - My Local

我希望以ms为单位转换为时间戳。但是，因为我只从调用者那里获得本地时间字符串 “2010-01-25 11：13：34.384”

如果我这样做：

// ts is "2010-01-25 11:13:34.384" (My Local)
boost::posix_time::ptime t(boost::posix_time::time_from_string(ts));
boost::posix_time::ptime end(boost::gregorian::date(1970,1,1));
boost::posix_time::time_duration dur = t - end;
// epoch is 1264418014384
// 2010-01-25 11:13:34.384 (GMT)  -- But I want 2010-01-25 03:13:34.384
// 2010-01-25 19:13:34.384 (My Local) -- But I want 2010-01-25 11:13:34.384
long long epoch = dur.total_milliseconds();

有没有办法告诉boost :: posix_time，它收到的ts字符串是否属于My Local时区？

Answer 1

我认为您应该使用处理时区的boost::local_date_time。文档中的示例与您尝试执行的操作非常相似：http://www.boost.org/doc/libs/1_41_0/doc/html/date_time/examples.html#date_time.examples.seconds_since_epoch

Answer 2

我在本地树中有这个（省略了名称空间前缀）：

    /// wall-clock translation to UTC
    const ptime from_wall_clock( const ptime& value,
                                 const time_zone_ptr& from )
    {
        assert( from.get());

        // interpret as local time
        const local_date_time from_local( value.date(),
            value.time_of_day(), from,
            local_date_time::NOT_DATE_TIME_ON_ERROR );

        // get UTC
        return from_local.utc_time();
    }

具体时区在boost :: posix_time :: ptime中

2 个答案: