Question

我只有php函数，我想使用JS警告框返回警报消息。

当我执行第一个if条件时，警报工作正常。但是一旦我添加其他警报框就不起作用（== 2和3）。

任何想法我做错了什么？

谢谢！

$(document).ready( function() {

if (<?php echo error_for('fileTmpLoc') ?>==1)
{
alert("Error: No image was selected.");
}
if (<?php echo error_for('fileTmpLoc') ?>==2)
{
alert("Error: Your file was too large. It was larger than 3.5 Megabytes in size.");
}
if (<?php echo error_for('fileTmpLoc') ?>==3)
{
alert("Error: Your file is too small. It was smaller than 200 KB in size.");
}

}）;

Answer 1

我没有对此进行测试，但您是否尝试过使用if else语句？

$(document).ready( function() {

if (<?php echo error_for('fileTmpLoc') ?>==1)
{
   alert("Error: No image was selected.");
}
else if (<?php echo error_for('fileTmpLoc') ?>==2)
{
   alert("Error: Your file was too large. It was larger than 3.5 Megabytes in size.");
}
else if (<?php echo error_for('fileTmpLoc') ?>==3)
{
   alert("Error: Your file is too small. It was smaller than 200 KB in size.");
}

});

Answer 2

您还可以通过PHP处理错误条件检查和JS警报输出，例如：

$(document).ready( function() {
<?php 
    switch(error_for('fileTmpLoc')) {
        case 1 : echo 'alert("Error: No image was selected.");';
                 break;
        case 2 : echo 'alert("Error: Your file was too large. It was larger than 3.5 Megabytes in size.");';
                 break;
        case 3 : echo 'alert("Error: Your file is too small. It was smaller than 200 KB in size.");';
                 break;
    }
?>
});

JS如果条件警报

2 个答案: