计算C中的特定字符？

Question

while ((temp = fgetc(fp)) != EOF)
  {

  if(temp == '\n')
  {
      chars++;
      lines++;
      if((temp = fgetc(fp)) != EOF && (temp == '(' || temp == ')' || temp == '{' || temp == '}'))
          {
              chars++;
              brackets++;
          }
      }
  }

基本上我想计算随机c文件中的每个（），{}和行。这个循环计算行很好，但无法统计所有指定的符号。知道为什么会这样吗？

Answer 1

考虑一个简单的状态机结构，如：

int ch;

while ((ch = getc(fp)) != EOF) {
  switch (ch) {
  case '\n':
     chars++;
     lines++;
     break;
  case '(': case ')': /* ... */
     chars++;
     brackets++;
     break;
  }
}

Answer 2

while ((temp = getc(fp)) != EOF)
{
   chars++;
   if(temp == '\n')
   {
      lines++;
      continue;
   }
   if(temp == '(' || temp == ')' || temp == '{' || temp    == '}')
   {
          brackets++;
   }
 }

Answer 3

while ((temp = fgetc(fp)) != EOF)
{
    if(temp == '\n')
        lines++;
    else if (temp == '(' || temp == ')') // include other brackets
        brakets++;

    chars++; // it appears that you want to count them all?
}