Question

如何使用Javascript / jQuery发布到弹出窗口？

var eids = selected_Ids.join();
var url =  'http://www.zyx.com';
$.post (url, {
    eId : eids
},
function (data) {
    // newpage = result;
    var new_window = window.open(url,  "abc");
});

弹出窗口不会出现。我做错了什么。

Answer 1

 function formPost(actionUrl, a) {
        var sHTML = "<form id='form1' action='" + actionUrl + "' method='post'>";

        for (var i = 0; i < a.length; i = i + 2) {
            sHTML += "<input name='" + a[i] + "' type='hidden' value='" + a[i + 1] + "' />";
        }

        sHTML += "</form>";
        var ooo = window.open("", "test");
        ooo.document.body.innerHTML = sHTML;
        ooo.form1.submit();
    }

只需调用此函数

formPost('http://www.zyx.com', ["key1", "111", "key2", "222"])

它在IE和Chrome中运行良好

享受它〜：）

将数据发布到弹出窗口

1 个答案: