例如, 该表有3行3列:
姓名年龄性别
彼得25米
约翰29米
Alex 25 M
我想查询表格并获取
姓名年龄性别
彼得25米
约翰29
亚历克斯
我尝试的方法:
SELECT DISTINCT Name,Age,Gender FROM table
输出仍然是
姓名年龄性别
彼得25米
约翰29米
Alex 25 M
如何实现每个字段没有冗余条目的表?感谢。
感谢大家的帮助,特别是donPablo的帮助。 这是我的VBA代码来实现这一目标。由于我对VBA完全不熟悉,因此代码可能不是非常干净和高效。但至少它有效。
Option Compare Database
Sub ReadDistinctValue()
Dim d As Database
Dim rs As Recordset
Dim FN As Field, Age As Field, Sex As Field
Set d = CurrentDb()
Set rs = d.OpenRecordset("Table1")
Set FN = rs.Fields("FN")
Set Age = rs.Fields("Age")
Set Sex = rs.Fields("Sex")
d.Execute "CREATE TABLE Table4 (FN Text,Age Text,Sex Text)"
While Not rs.EOF
If CheckFN(FN) = False Then
Call WriteFN(FN)
End If
If CheckAge(Age) = False Then
Call WriteAge(Age)
End If
If CheckSex(Sex) = False Then
Call WriteSex(Sex)
End If
rs.MoveNext
Wend
rs.Close
End Sub
Function CheckFN(FN As Field) As Boolean
Dim d As Database
Dim rs_new As Recordset
Dim FN_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set FN_new = rs_new.Fields("FN")
CheckFN = False
Do While Not rs_new.EOF
If FN_new = FN Then
CheckFN = True
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
Function WriteFN(FN As Field)
Dim d As Database
Dim rs_new As Recordset
Dim FN_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set FN_new = rs_new.Fields("FN")
If Not rs_new.EOF Then
rs_new.MoveFirst
End If
Do While True
If rs_new.EOF Then
rs_new.AddNew
FN_new = FN
rs_new.Update
Exit Do
End If
If IsNull(FN_new.Value) Then
rs_new.Edit
FN_new = FN
rs_new.Update
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
Function CheckAge(Age As Field) As Boolean
Dim d As Database
Dim rs_new As Recordset
Dim Age_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set Age_new = rs_new.Fields("Age")
CheckAge = False
Do While Not rs_new.EOF
If Age_new = Age Then
CheckAge = True
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
Function WriteAge(Age As Field)
Dim d As Database
Dim rs_new As Recordset
Dim Age_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set Age_new = rs_new.Fields("Age")
If Not rs_new.EOF Then
rs_new.MoveFirst
End If
Do While True
If rs_new.EOF Then
rs_new.AddNew
Age_new = Age
rs_new.Update
Exit Do
End If
If IsNull(Age_new.Value) Then
rs_new.Edit
Age_new = Age
rs_new.Update
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
Function CheckSex(Sex As Field) As Boolean
Dim d As Database
Dim rs_new As Recordset
Dim Sex_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set Sex_new = rs_new.Fields("Sex")
CheckSex = False
Do While Not rs_new.EOF
If Sex_new = Sex Then
CheckSex = True
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
Function WriteSex(Sex As Field)
Dim d As Database
Dim rs_new As Recordset
Dim Sex_new As Field
Set d = CurrentDb()
Set rs_new = d.OpenRecordset("Table4")
Set Sex_new = rs_new.Fields("Sex")
If Not rs_new.EOF Then
rs_new.MoveFirst
End If
Do While True
If rs_new.EOF Then
rs_new.AddNew
Sex_new = Sex
rs_new.Update
Exit Do
End If
If IsNull(Sex_new.Value) Then
rs_new.Edit
Sex_new = Sex
rs_new.Update
Exit Do
End If
rs_new.MoveNext
Loop
rs_new.Close
End Function
答案 0 :(得分:0)
通过命名三列,您将检索该组值的不同组合。
如果您需要不同值的列表,请在选择中单独命名。
SELECT DISTINCT Name FROM table
SELECT DISTINCT Age FROM table
SELECT DISTINCT Gender FROM table
如果您尝试按照示例中的方式显示它们,则必须通过某些GUI功能来完成。 SQL数据库引擎不擅长显示技巧,只是处理数据。
答案 1 :(得分:0)
我已经稍微扩展了表值,只是为了看看会发生什么 -
FN Age Sex
Alice 28 F
Ben 19 M
Charles 33 M
Doug 23 M
Elaine 21 F
Frank 25 M
Gwen 28 F
Helen 33 F
Alice 17 F
Ben 21 F
然后我为FN开发了一个查询,后来推广到所有三个字段 -
线索是对每个FN / AGE / SEX进行排序,然后加入该seq# -
SELECT
AB.fn,
CD.age,
EF.sex
FROM
((SELECT A.fn, Count(B.fn) AS CNTfn
FROM
(SELECT DISTINCT fn FROM table1) AS A,
(SELECT DISTINCT fn FROM table1) AS B
WHERE B.fn <= A.fn
GROUP BY A.fn) AS AB
LEFT JOIN
(SELECT C.age, Count(D.age) AS CNTage
FROM
(SELECT DISTINCT age FROM table1) AS C,
(SELECT DISTINCT age FROM table1) AS D
WHERE D.age <= C.age
GROUP BY C.age) AS CD
ON AB.cntfn = CD.cntage)
LEFT JOIN
(SELECT E.sex, Count(F.sex) AS CNTsex
FROM
(SELECT DISTINCT sex FROM table1) AS E,
(SELECT DISTINCT sex FROM table1) AS F
WHERE F.sex <= E.sex
GROUP BY E.sex) AS EF
ON AB.cntfn = EF.CNTsex;
这给出了所需的结果 -
FN AGE SEX
Alice 17 F
Ben 19 M
Charles 21
Doug 23
Elaine 25
Frank 28
Gwen 33
Helen
我在示例表中更改了Sex,并将以下内容添加到un-Distinct整个表的第一个序列中,并将ON ...更改为XZ.cntall ...
(SELECT X.FN & X.AGE & X.SEX, Count(*) AS CNTall
FROM
(SELECT DISTINCT FN, AGE, SEX FROM table1) AS X,
(SELECT DISTINCT FN, AGE, SEX FROM table1) AS Z
WHERE Z.FN & Z.AGE & Z.SEX <= X.FN & X.AGE & X.SEX
GROUP BY X.FN, X.AGE, X.SEX) as XZ
现在获得这些结果
fn age sex
Alice 17 M
Ben 19 N
Charles 21 O
Doug 23 P
Elaine 25 Q
Frank 28 R
Gwen 33 W
Helen X
Y
Z
答案 2 :(得分:-2)
可能有一个SQL解决方案。我不断惊讶于可以做些什么。但是,我的答案是,这是VBA的完美应用。