我正在尝试绑定来自Web服务的数据,然后使用该数据预填充表单。除单个多选元素外,所有表单控件都正确绑定。如果我手动选择一个选项,模型会更新。以下是我的控制器:
myApp.controller('AdminVideosEditCtrl', [
'$scope',
'$http',
'$routeParams',
'$location',
function($scope, $http, $routeParams, $location) {
$http.get('/videos/' + $routeParams.videoId + '?embed=presenters').success(function(data) {
$scope.video = data.data
// Load providers
$http.get('/providers').success(function(data) {
$scope.providers = data.data;
// Load Presenters
$http.get('/presenters').success(function(data) {
$scope.presenters = data.data;
});
});
});
}
]);
最终请求返回后,我的模型看起来像这样(通过{{ video | json }}
输出):
{
"id": "ca3ca05a-834e-47b1-aaa1-3dbe38338ca9",
"title": "Doloremque iure consequatur quam ea.",
"is_public": false,
"is_visible": true,
"url": "http://someurl.com/",
"provider_id": "1b4d18eb-d56c-41ae-9431-4c058a32d651",
"level_id": "38ed7286-da05-44b9-bfb9-e1278088d229",
"duration": "17:38",
"transcript_file": "rerum-sint-voluptatum.md",
"presenters": [
{
"id": "5111531d-5f2a-45f5-a0c4-4fa3027ff249",
"first_name": "First",
"last_name": "Last",
"full_name": "First Last"
}
],
"provider": {
"id": "1b4d18eb-d56c-41ae-9431-4c058a32d651",
"title": "You Tube"
}
}
以下是我在视图中多选的内容:
<div class="form-group">
<label for="presenters" class="col-lg-2 control-label">Presenters</label>
<div class="col-lg-10">
<select multiple="multiple" class="form-control" id="presenters" ng-model="video.presenters" ng-options="presenter.full_name for ( id , presenter ) in presenters">
</select>
</div>
</div>
select
元素填充正确,我希望它默认选择“First Last”元素,但不选择任何内容。我知道我的模型是正确初始化的,因为如果我手动选择元素,模型中的任何内容都不会更改(如果我选择了不同的元素,但仍保留与初始页面加载时相同的结构)。
我尝试添加$scope.$apply
来电,我也试过了$scope.$root.$eval()
,这两种情况都不起作用。
更新
演示者模型(包含所有演示者)在从服务中获取之后看起来像这样(名称已被更改以保护无辜者):
[
{
"id": "47b6e945-2d4b-44c2-b44b-adb96460864d",
"first_name": "First",
"last_name": "Last",
"full_name": "First Last"
},
{
"id": "5111531d-5f2a-45f5-a0c4-4fa3027ff249",
"first_name": "One",
"last_name": "Two",
"full_name": "One Two"
},
{
"id": "7cb1e44b-2806-4576-80b2-ae730ad356f7",
"first_name": "Three",
"last_name": "Four",
"full_name": "Three Four"
}
]
答案 0 :(得分:2)
将它放在控制器的底部
$scope.video.presenters.forEach(function(obj, idx){
$scope.presenters.forEach(function(presenter, jdx){
if (obj.id === presenter.id) {
$scope.video.presenters = [$scope.presenters[jdx]]
}
});
});
<强> JSFIDDLE 强>
这更加强大,因为您可能希望预先选择多个选项。此解决方案将每个选定的选项推送到一个数组中,然后将其分配给$scope.video.presenters
模型
var selectedOptions = [];
$scope.video.presenters.forEach(function (obj, idx) {
$scope.presenters.forEach(function (presenter, idj) {
if (obj.id === presenter.id) {
selectedOptions.push($scope.presenters[idj]);
$scope.video.presenters = selectedOptions;
}
});
<强> JSFIDDLE 强>
注意:理想情况下,您应该使用id
键作为对象的唯一键。
此解决方案假定并且仅适用于预选一个选项。