Question

我有两个日期：

String date_1="yyyyMMddHHmmss";
String date_2="yyyyMMddHHmmss";

我想打印差异，如：

2d 3h 45m

我该怎么做？谢谢！

Answer 1

DateTimeUtils obj = new DateTimeUtils();
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/M/yyyy hh:mm:ss");

try {
    Date date1 = simpleDateFormat.parse("10/10/2013 11:30:10");
    Date date2 = simpleDateFormat.parse("13/10/2013 20:35:55");

    obj.printDifference(date1, date2);

} catch (ParseException e) {
    e.printStackTrace();
}

//1 minute = 60 seconds
//1 hour = 60 x 60 = 3600
//1 day = 3600 x 24 = 86400
public void printDifference(Date startDate, Date endDate) { 
    //milliseconds
    long different = endDate.getTime() - startDate.getTime();

    System.out.println("startDate : " + startDate);
    System.out.println("endDate : "+ endDate);
    System.out.println("different : " + different);

    long secondsInMilli = 1000;
    long minutesInMilli = secondsInMilli * 60;
    long hoursInMilli = minutesInMilli * 60;
    long daysInMilli = hoursInMilli * 24;

    long elapsedDays = different / daysInMilli;
    different = different % daysInMilli;

    long elapsedHours = different / hoursInMilli;
    different = different % hoursInMilli;

    long elapsedMinutes = different / minutesInMilli;
    different = different % minutesInMilli;

    long elapsedSeconds = different / secondsInMilli;

    System.out.printf(
        "%d days, %d hours, %d minutes, %d seconds%n", 
        elapsedDays, elapsedHours, elapsedMinutes, elapsedSeconds);
}

输出是：

startDate : Thu Oct 10 11:30:10 SGT 2013
endDate : Sun Oct 13 20:35:55 SGT 2013
different : 291945000
3 days, 9 hours, 5 minutes, 45 seconds

Answer 2

这适用于转换为String作为奖励;）

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.activity_main);

    try {
        //Dates to compare
        String CurrentDate=  "09/24/2015";
        String FinalDate=  "09/26/2015";

        Date date1;
        Date date2;

        SimpleDateFormat dates = new SimpleDateFormat("MM/dd/yyyy");

        //Setting dates
        date1 = dates.parse(CurrentDate);
        date2 = dates.parse(FinalDate);

        //Comparing dates
        long difference = Math.abs(date1.getTime() - date2.getTime());
        long differenceDates = difference / (24 * 60 * 60 * 1000);

        //Convert long to String
        String dayDifference = Long.toString(differenceDates);

        Log.e("HERE","HERE: " + dayDifference);

    } catch (Exception exception) {
        Log.e("DIDN'T WORK", "exception " + exception);
    }
}

Answer 3

Date userDob = new SimpleDateFormat("yyyy-MM-dd").parse(dob);
Date today = new Date();
long diff =  today.getTime() - userDob.getTime();
int numOfDays = (int) (diff / (1000 * 60 * 60 * 24));
int hours = (int) (diff / (1000 * 60 * 60));
int minutes = (int) (diff / (1000 * 60));
int seconds = (int) (diff / (1000));

Answer 4

它会给你几个月的差异

long milliSeconds1 = calendar1.getTimeInMillis();
long milliSeconds2 = calendar2.getTimeInMillis();
long periodSeconds = (milliSeconds2 - milliSeconds1) / 1000;
long elapsedDays = periodSeconds / 60 / 60 / 24;

System.out.println(String.format("%d months", elapsedDays/30));

Answer 5

DateTime start = new DateTime(2013, 10, 20, 5, 0, 0, Locale);
DateTime end = new DateTime(2013, 10, 21, 13, 0, 0, Locale);
Days.daysBetween(start.toLocalDate(), end.toLocalDate()).getDays()

它返回给定两个日期之间的天数，其中DateTime来自joda库

Answer 6

短＆amp;甜

/** * Get a diff between two dates * * @param oldDate the old date * @param newDate the new date * @return the diff value, in the days */ public static long getDateDiff(SimpleDateFormat format, String oldDate, String newDate) { try { return TimeUnit.DAYS.convert(format.parse(newDate).getTime() - format.parse(oldDate).getTime(), TimeUnit.MILLISECONDS); } catch (Exception e) { e.printStackTrace(); return 0; } }

<强>用法：

int dateDifference = (int) getDateDiff(new SimpleDateFormat("dd/MM/yyyy"), "29/05/2017", "31/05/2017"); System.out.println("dateDifference: " + dateDifference);

<强>输出：

dateDifference: 2

Answer 7

您可以使用此方法计算时间差（以毫秒为单位），并以秒，分钟，小时，天，月和年为单位获取输出。

您可以从此处下载课程：DateTimeDifference GitHub Link

简单易用

long currentTime = System.currentTimeMillis();
long previousTime = (System.currentTimeMillis() - 864000000); //10 days ago

Log.d("DateTime: ", "Difference With Second: " + AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.SECOND));
Log.d("DateTime: ", "Difference With Minute: " + AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.MINUTE));

您可以比较以下示例

if(AppUtility.DateTimeDifference(currentTime, previousTime, AppUtility.TimeDifference.MINUTE) > 100){
    Log.d("DateTime: ", "There are more than 100 minutes difference between two dates.");
}else{
    Log.d("DateTime: ", "There are no more than 100 minutes difference between two dates.");
}

Answer 8

我安排了一点。效果很好。

@SuppressLint("SimpleDateFormat") SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd MM yyyy");
    Date date = new Date();
    String dateOfDay = simpleDateFormat.format(date);

    String timeofday = android.text.format.DateFormat.format("HH:mm:ss", new Date().getTime()).toString();

    @SuppressLint("SimpleDateFormat") SimpleDateFormat dateFormat = new SimpleDateFormat("dd MM yyyy hh:mm:ss");
    try {
        Date date1 = dateFormat.parse(06 09 2018 + " " + 10:12:56);
        Date date2 = dateFormat.parse(dateOfDay + " " + timeofday);

        printDifference(date1, date2);

    } catch (ParseException e) {
        e.printStackTrace();
    }

@SuppressLint("SetTextI18n")
private void printDifference(Date startDate, Date endDate) {
    //milliseconds
    long different = endDate.getTime() - startDate.getTime();

    long secondsInMilli = 1000;
    long minutesInMilli = secondsInMilli * 60;
    long hoursInMilli = minutesInMilli * 60;
    long daysInMilli = hoursInMilli * 24;

    long elapsedDays = different / daysInMilli;
    different = different % daysInMilli;

    long elapsedHours = different / hoursInMilli;
    different = different % hoursInMilli;

    long elapsedMinutes = different / minutesInMilli;
    different = different % minutesInMilli;

    long elapsedSeconds = different / secondsInMilli;

Toast.makeText(context, elapsedDays + " " + elapsedHours + " " + elapsedMinutes + " " + elapsedSeconds, Toast.LENGTH_SHORT).show();
}

Answer 9

您可以将其概括为一个允许您选择输出格式的函数

private String substractDates(Date date1, Date date2, SimpleDateFormat format) {
    long restDatesinMillis = date1.getTime()-date2.getTime();
    Date restdate = new Date(restDatesinMillis);

    return format.format(restdate);
}

现在这是一个简单的函数调用，小时，分钟和秒的差异：

SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

try {
    Date date1 = formater.parse(dateEnd);
    Date date2 = formater.parse(dateInit);

    String result = substractDates(date1, date2, new SimpleDateFormat("HH:mm:ss"));

    txtTime.setText(result);
} catch (ParseException e) {
    e.printStackTrace();
}

Answer 10

当您使用Date()来计算小时差异时，需要在UTC中配置SimpleDateFormat()，否则由于夏令时而导致一小时错误。

Answer 11

我用这个：以毫秒发送开始和结束日期

public int GetDifference(long start,long end){
    Calendar cal = Calendar.getInstance();
    cal.setTimeInMillis(start);
    int hour = cal.get(Calendar.HOUR_OF_DAY);
    int min = cal.get(Calendar.MINUTE);
    long t=(23-hour)*3600000+(59-min)*60000;

    t=start+t;

    int diff=0;
    if(end>t){
        diff=(int)((end-t)/ TimeUnit.DAYS.toMillis(1))+1;
    }

    return  diff;
}

Answer 12

这是现代的答案。这对于使用Java 8或更高版本的用户来说是好事（对于大多数Android手机来说还不行，或者对外部库感到满意。）

    String date1 = "20170717141000";
    String date2 = "20170719175500";

    DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss");
    Duration diff = Duration.between(LocalDateTime.parse(date1, formatter), 
                                     LocalDateTime.parse(date2, formatter));

    if (diff.isZero()) {
        System.out.println("0m");
    } else {
        long days = diff.toDays();
        if (days != 0) {
            System.out.print("" + days + "d ");
            diff = diff.minusDays(days);
        }
        long hours = diff.toHours();
        if (hours != 0) {
            System.out.print("" + hours + "h ");
            diff = diff.minusHours(hours);
        }
        long minutes = diff.toMinutes();
        if (minutes != 0) {
            System.out.print("" + minutes + "m ");
            diff = diff.minusMinutes(minutes);
        }
        long seconds = diff.getSeconds();
        if (seconds != 0) {
            System.out.print("" + seconds + "s ");
        }
        System.out.println();
    }

打印

2d 3h 45m

在我看来，优势并不是它更短（它并不多），但将计算留给标准库的错误更少，并为您提供更清晰的代码。这些都是很大的优势。读者不必承担识别24,60和1000等常量并验证它们是否正确使用。

我正在使用现代Java日期＆amp;时间API（在JSR-310中描述，也以此名称已知）。要在Android上使用此功能，请获取ThreeTenABP，请参阅this question: How to use ThreeTenABP in Android Project。要将其与其他Java 6或7一起使用，请获取ThreeTen Backport。使用Java 8及更高版本，它是内置的。

使用Java 9，它会更容易一些，因为Duration类扩展了方法，可以分别为你提供日期部分，小时部分，分钟部分和秒部分，这样你就不需要减法了。请参阅my answer here中的示例。

Answer 13

尝试一下。

int day = 0;
        int hh = 0;
        int mm = 0;
        try {
            SimpleDateFormat dateFormat = new SimpleDateFormat("dd-MMM-yyyy 'at' hh:mm aa");
            Date oldDate = dateFormat.parse(oldTime);
            Date cDate = new Date();
            Long timeDiff = cDate.getTime() - oldDate.getTime();
            day = (int) TimeUnit.MILLISECONDS.toDays(timeDiff);
            hh = (int) (TimeUnit.MILLISECONDS.toHours(timeDiff) - TimeUnit.DAYS.toHours(day));
            mm = (int) (TimeUnit.MILLISECONDS.toMinutes(timeDiff) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(timeDiff)));



        } catch (ParseException e) {
            e.printStackTrace();
        }

        if (mm <= 60 && hh!= 0) {
            if (hh <= 60 && day != 0) {
                return day + " DAYS AGO";
            } else {
                return hh + " HOUR AGO";
            }
        } else {
            return mm + " MIN AGO";
        }

两个日期之间的Android差异

13 个答案: