Question

我有以下mongo shell代码，我试图在我的php应用程序中使用。它基本上在一个时间范围内取800个均匀分布的值，用于图表。

var map = function () {
if (endTime < 0) {
    var start = new ISODate("2013-09-01T00:00:00.000Z");
    var end = new ISODate("2013-11-01T00:00:00.000Z");
    var startMilli = start.getTime(); 
    var endMilli = end.getTime(); 
    var interval = endMilli - startMilli; 
    delta = interval / 800;
    endTime = startMilli + delta;
    }
if (endTime < this.date.getTime()) { 
    resArray = {};
    while (endTime < this.date.getTime()) {
        endTime += delta; 
    }
}
    var id = this.homeId + this.sensor;
if (typeof resArray[id] == 'undefined') {
resArray[id] = 1;
emit({ 
    homeId: this.homeId, 
    sensor: this.sensor, 
    date: this.date, 
    val: this.val
}, { 
    x: 1 
});
}
};
var reduce = function (key, values) { 
return values[0];
};


db.passiv.mapReduce(
map, 
reduce, 
{ query: 
    { homeId: 35600, 
      sensor : { 
        $in :[ "z1t","ts1"] 
    }, 
    date : { 
        $gte : new ISODate("2013-09-01T00:00:00.000Z"), 
        $lte : new ISODate("2013-11-01T00:00:00.000Z")
    } }, 
    scope : { 
        resArray : {}, 
        delta : -1, 
        endTime : -1 
    }, 
    out: 'TEST1', 
    sort : { 
        date:1 
    } 
});

它在shell中执行正常但我尝试将其转换为php并没有给我任何结果：

$from = '2013-09-01T00:00:00.000Z';
$to = '2013-11-01T00:00:00.000Z';

$map = new MongoCode("
var map = function () {
if (endTime < 0) {
var start = new ISODate(".$from.");
var end = new ISODate(".$to.");
var startMilli = start.getTime();
var endMilli = end.getTime();
var interval = endMilli - startMilli;
delta = interval / 800;
endTime = startMilli + delta;
}
if (endTime < this.date.getTime()) {
resArray = {};
while (endTime < this.date.getTime()) {
    endTime += delta;
}
}
var id = this.homeId + this.sensor;
if (typeof resArray[id] == 'undefined') {
resArray[id] = 1;
emit({
    homeId: this.homeId,
    sensor: this.sensor,
    date: this.date,
    val: this.val},
    { x: 1 });
}
};");

$reduce = new MongoCode('
var reduce = function (key, values) {
    return values[0];
};');

$constraint = array('homeId' => 32168);
$date = array('$gte' => new MongoDate(1377986400), '$lt' => new MongoDate(1383260400));
$condition = array_merge($constraint, $date, array("sensor" => array('$in' => array('z1t', 'ts1'))));
$rs = $passivCollection->command(
array(
    "mapreduce" => "passiv",
    "query" => $condition,
    "map" => $map,
    "reduce" => $reduce,
    "scope" => array(
        "resArray" => array(),
        "delta" => -1,
        "endTime" => -1
    ),
    "out" => "TEST1",
    "sort" => array("date" => 1)
));

不知何故，我认为最终命令中的范围不能正常工作，我似乎无法在任何地方找到任何有用的范围。非常感谢任何帮助。

Answer 1

在PHP中进行Map Reduce的一个很好的例子位于：＃{3}}，例如＃3。

基本上你遇到的一个问题是MongoCode对象不再代表anon函数，而是一个无法返回的变量。

相反，您需要定义以下功能：

$reduce = new MongoCode('
function (key, values) {
    return values[0];
};
');

我认为应该修复它。

修改

您的编辑中存在PHP问题：

$start = new MongoDate(strtotime("2013-09-01 00:00:00"));
$end = new MongoDate(strtotime("2013-11-01 00:00:00"));
$constraint = array('homeId' => '32168');
$date = array('$gte' => $start, '$lt' => $end);
$sensors = array('z1t');
$condition = array_merge($constraint, $date, array("sensor" => array('$in' => $sensors)));
var_dump($condition);
$tt = $passivCollection->selectCollection('passiv')->count($date);
var_dump($tt);

您正在使用：

$date = array('$gte' => $start, '$lt' => $end);

如果没有定义字段，则应搜索。尝试：

$start = new MongoDate(strtotime("2013-09-01 00:00:00"));
$end = new MongoDate(strtotime("2013-11-01 00:00:00"));
$constraint = array('homeId' => '32168');
$date = array('date' => array('$gte' => $start, '$lt' => $end));
$sensors = array('z1t');
$condition = array_merge($constraint, $date, array("sensor" => array('$in' => $sensors)));
var_dump($condition);
$tt = $passivCollection->selectCollection('passiv')->count($date);
var_dump($tt);

date字符串位于：

$date = array('date' => array('$gte' => $start, '$lt' => $end));

将替换为您的字段名称。

转换mongo map将代码转换为php

1 个答案:

修改