大家好,你对这些代码有所了解。 textarea提交到数据库。因为我有一个connection.php但它没有插入数据库请帮助我使用选项textarea。你能帮助我phpmyadmin SQL我应该把什么名字,类型等放到tnx
select.html
<html lang="en">
<title>NTF Catering Service</title>
<meta charset="utf-8">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"> </script>
<script src="js/js.1.js" type="text/javascript"></script>
</head>
<body>
<form action="create.php" method="post">
<select multiple="multiple" class="options" id="textarea">
<option value="item1">Item 1</option>
<option value="item2">Item 2</option>
<option value="item3">Item 3</option>
<option value="item4">Item 4</option>
<option value="item5">Item 5</option>
</select>
<button id="copy">Copy</button>
<button id="remove">Remove</button>
<select id="textarea2" multiple class="remove">
<input type="submit" name="submit" />
</form>
</select>
</html>
connection.php
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$db = "copy";
$conn = mysql_connect($dbhost,$dbuser,$dbpass);
mysql_select_db($db);
?>
submit.php
<?php
include 'connection.php';
$food1 = $_POST['food1'];
$food2 = $_POST['food2'];
$food3 = $_POST['food3'];
$food4 = $_POST['food4'];
$food5 = $_POST['food5'];
if(!$_POST['submit']) {
echo "please fill out the form";
header('Location: select.html');
} else {
$sql = "INSERT INTO remove(food1, food2, food3, food4, food5) VALUES ('".$food1."', '".$food2."', '".$food3."','".$food4."','".$food5."');";
mysql_query($link, $sql);
echo "User has been added!";
header('Location: select.html');
}
?>
答案 0 :(得分:-1)
让您的INSERT INTO
声明成为以下形式:
$sql = "INSERT INTO remove(food1, food2, food3, food4, food5) VALUES ($food1, $food2, $food3, $food4, $food5)";
答案 1 :(得分:-1)
您的行为有误,应为submit.php
另外请不要使用mysql_*
函数,因为它们已被弃用。
改为使用mysqli
或PDO
。还可以使用prepared statements
来阻止SQL注入。
connection.php 的示例:
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$db = "copy";
$conn = mysqli_connect($dbhost,$dbuser,$dbpass,$db);
?>
submit.php 的示例(带有预备声明):
<?php
include 'connection.php';
$food1 = $_POST['food1'];
$food2 = $_POST['food2'];
$food3 = $_POST['food3'];
$food4 = $_POST['food4'];
$food5 = $_POST['food5'];
if(!$_POST['submit']) {
echo "please fill out the form";
header('Location: select.html');
} else {
$sql = "INSERT INTO remove(food1, food2, food3, food4, food5) VALUES (?,?,?,?,?);";
$stmt = mysqli_prepare($conn, $sql);
mysqli_stmt_bind_param($stmt,"sssss",$food1,$food2,$food3,$food4,$food5);
mysqli_stmt_execute($stmt);
echo "User has been added!";
header('Location: select.html');
}
?>