Question

我有一个名为ps_megasearch_attributes的数据库。为此，我的数据库查询就像这样

CREATE TABLE IF NOT EXISTS `ps_megasearch_attributes` (
  `attribute_id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `attribute_name` text NOT NULL,
  PRIMARY KEY (`attribute_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8  ;

--
-- Dumping data for table `ps_megasearch_attributes`
--

INSERT INTO `ps_megasearch_attributes` (`attribute_id`, `attribute_name`) VALUES
(1, 'Color');

现在从数据库中获取值我在php中有这个代码

<?php 
$attribute_name_fetch = mysqli_query($con,"SELECT `attribute_name` FROM `ps_megasearch_attributes` ORDER BY `attribute_id` DESC LIMIT 1 " );
while($attributes_list=mysqli_fetch_array($attribute_name_fetch )){
  foreach($attributes_list as $attribute_name) {
    echo $attribute_name;
  }
}

?>

但这一次显示返回结果数组两次。那么有人可以告诉我该怎么做吗？任何帮助都会非常明显。

Answer 1

mysqli_fetch_array

mysqli_result :: fetch_array - mysqli_fetch_array - 将结果行提取为关联行，数字数组或两者

您不需要foreach循环。

while($attributes_list=mysqli_fetch_array($attribute_name_fetch )){
    echo $attributes_list['attribute_name']
}

Answer 2

你有2个循环 - while和foreach。尝试：

<?php 
$attribute_name_fetch = mysqli_query($con,"SELECT `attribute_name` FROM `ps_megasearch_attributes` ORDER BY `attribute_id` DESC LIMIT 1 " );
$attributes_list=mysqli_fetch_array($attribute_name_fetch);
foreach($attributes_list as $attribute_name) {
  echo $attribute_name;
}
?>

MySQL返回结果在while循环中显示两次？

2 个答案: