SQL过程错误精确提取返回超过请求的行数

时间:2014-01-22 04:21:00

标签: sql stored-procedures oracle-sqldeveloper

我有下面的SQL过程,它从SQL DEveloper

运行时显示以下错误
ERROR Message: 
    ORA-01422: exact fetch returns more than requested number of rows



PROCEDURE SP_ENABLE_CONST(P_ARCH_BATCH_ID VARCHAR) IS


TABLELIST VARCHAR2(100);
SQL_QUERY VARCHAR2(4000);
RESULT_COL INT;
RESULT_CONST_COL VARCHAR2(1000);


BEGIN
/*LOOP will return three tables designated in table_name */
FOR TEMP2_VAR_TEST IN (SELECT TABLE_NAME FROM SYS.ALL_TABLES WHERE TABLE_NAME LIKE 'TEST%')

/*each loop the table_name returned will be used in SQL_QUERY */
  LOOP

      SQL_QUERY := 'SELECT CONSTRAINT_NAME FROM USER_CONS_COLUMNS WHERE TABLE_NAME = :1';

      DBMS_OUTPUT.PUT_LINE(SQL_QUERY); 

/*select statement will return more than one row containing table constraints*/
**ERROR on this part since RESULT_CONST_COL cannot contain more than one row
      EXECUTE IMMEDIATE SQL_QUERY INTO RESULT_CONST_COL USING TEMP2_VAR_TEST.TABLE_NAME;

      DBMS_OUTPUT.PUT_LINE('CONSTRAINT_NAME' || RESULT_CONST_COL);

  END LOOP;     
  END SP_ENABLE_CONST;
END PK_ARCHIVE_PROCESS_TEST;

我知道错误是由result_const_col引起的,它是VARCHAR2类型但不知道用什么来存储execute immediate命令返回的多行。我已阅读有关游标并试图使用它但仍然出错。提前谢谢。

更新1

按照您的建议修改了我的代码,但仍然遇到错误。

TYPE RESULT_CONST_COL IS TABLE OF VARCHAR2(1000);
VAR_OF_RESULT_CONST RESULT_CONST_COL;

TBL_CONSTRAINTS VARCHAR2(100);
TABLELIST VARCHAR2(100);
SQL_QUERY VARCHAR2(4000);
RESULT_COL INT;


BEGIN

FOR TEMP2_VAR_TEST IN (SELECT TABLE_NAME FROM SYS.ALL_TABLES WHERE TABLE_NAME LIKE 'TEST%')

  LOOP      
      SQL_QUERY := 'SELECT CONSTRAINT_NAME FROM USER_CONS_COLUMNS WHERE TABLE_NAME = :1';          
      DBMS_OUTPUT.PUT_LINE(SQL_QUERY); 

/*ERROR line 92*/
        EXECUTE IMMEDIATE SQL_QUERY USING TEMP2_VAR_TEST.TABLE_NAME
          RETURNING BULK COLLECT INTO VAR_OF_RESULT_CONST;      

        FOR I IN 1 .. VAR_OF_RESULT_CONST.COUNT LOOP
          DBMS_OUTPUT.PUT_LINE(VAR_OF_RESULT_CONST(i));
        END LOOP;       
  END LOOP;

当我尝试运行上面的代码时遇到此错误

ORA-06547: RETURNING clause must be used with INSERT, UPDATE, or DELETE statements
**ORA-06512: at "HSNIAPP.PK_ARCHIVE_PROCESS_TEST", line 92**
ORA-06512: at line 6
SELECT CONSTRAINT_NAME FROM USER_CONS_COLUMNS WHERE TABLE_NAME = :1

1 个答案:

答案 0 :(得分:2)

您必须将RESULT_CONST_COL声明为集合:

RESULT_CONST_COL IS TABLE OF VARCHAR2(1000);

然后使用BULK COLLECT INTO返回多行:

EXECUTE IMMEDIATE SQL_QUERY BULK COLLECT INTO RESULT_CONST_COL
 USING TEMP2_VAR_TEST.TABLE_NAME;

然后遍历集合中的返回结果以处理所有值:

FOR i IN 1 .. RESULT_CONST_COL.COUNT LOOP
 DBMS_OUTPUT.PUT_LINE(RESULT_CONST_COL(i));
 EXECUTE IMMEDIATE 'ALTER TABLE '|| TEMP2_VAR_TEST ||
  ' DISABLE CONSTRAINT ' || RESULT_CONST_COL(i);
END LOOP;