如何在java中实现可扩展哈希?

时间:2010-01-24 14:33:43

标签: java

extendible hashing是最好的散列方法之一,我想在java中创建程序,用于extenidble散列。有没有api可以做到这一点?我自己没有得到明确的算法,所以如果没有api,如果可能发布algoirhtm

8 个答案:

答案 0 :(得分:3)

我只是好奇,为什么你需要实现这样的算法?标准Java Map实现不适合您吗?如果你遇到一个桶负载过重的问题,你可能需要在选择非标准路由之前先看一下hashCode()方法。另一种选择也可以是查看GNU Trove提供的一些选项。

最后 - 与Extendible类似的算法是Cuckoo哈希。以下是一些信息:

http://en.wikipedia.org/wiki/Cuckoo_hashing

此处的源代码:

http://lmonson.com/blog/?page_id=99

答案 1 :(得分:1)

此文件定义HashTable类。哈希表中的键和值        属于Object类型。键不能为空。默认构造函数        创建一个最初有64个位置但不同的表        初始大小可以指定为构造函数的参数。        如果表格大于3/4满,则表格会增加。

public class HashTable {

  static private class ListNode {
       // Keys that have the same hash code are placed together
       // in a linked list.  This private nested class is used
       // internally to implement linked lists.  A ListNode
       // holds a (key,value) pair.  
     Object key;
     Object value;
     ListNode next;  // Pointer to next node in the list;
                     // A null marks the end of the list.
  }

  private ListNode[] table;  // The hash table, represented as
                             // an array of linked lists.

  private int count;  // The number of (key,value) pairs in the
                      // hash table.

  public HashTable() {
       // Create a hash table with an initial size of 64.
     table = new ListNode[64];
  }

  public HashTable(int initialSize) {
       // Create a hash table with a specified initial size.
       // Precondition: initalSize > 0.
     table = new ListNode[initialSize];
  }

  void dump() {
        // This method is NOT part of the usual interface for
        // a hash table.  It is here only to be used for testing
        // purposes, and should be removed before the class is 
        // released for general use.  This lists the (key,value)
        // pairs in each location of the table.
     System.out.println();
     for (int i = 0; i < table.length; i++) {
          // Print out the location number and the list of
          // key/value pairs in this location.
        System.out.print(i + ":");
        ListNode list = table[i]; // For traversing linked list number i.
        while (list != null) {
           System.out.print("  (" + list.key + "," + list.value + ")");
           list = list.next;
        }
        System.out.println();
     }
  } // end dump()

  public void put(Object key, Object value) {
        // Associate the specified value with the specified key.
        // Precondition:  The key is not null.
     int bucket = hash(key); // Which location should this key be in?
     ListNode list = table[bucket]; // For traversing the linked list
                                    // at the appropriate location.
     while (list != null) {
           // Search the nodes in the list, to see if the key already exists.
        if (list.key.equals(key))
           break;
        list = list.next;
     }
      // At this point, either list is null, or list.key.equals(key).
     if (list != null) {
          // Since list is not null, we have found the key.
          // Just change the associated value.
        list.value = value;
     }
     else {
          // Since list == null, the key is not already in the list.
          // Add a new node at the head of the list to contain the
          // new key and its associated value.
        if (count >= 0.75*table.length) {
             // The table is becoming too full.  Increase its size
             // before adding the new node.
           resize();
        }
        ListNode newNode = new ListNode();
        newNode.key = key;
        newNode.value = value;
        newNode.next = table[bucket];
        table[bucket] = newNode;
        count++;  // Count the newly added key.
     }
  }

  public Object get(Object key) {
        // Retrieve the value associated with the specified key
        // in the table, if there is any.  If not, the value
        // null will be returned.
     int bucket = hash(key);  // At what location should the key be?
     ListNode list = table[bucket];  // For traversing the list.
     while (list != null) {
            // Check if the specified key is in the node that
            // list points to.  If so, return the associated value.
        if (list.key.equals(key))
           return list.value;
        list = list.next;  // Move on to next node in the list.
     }
      // If we get to this point, then we have looked at every
      // node in the list without finding the key.  Return
      // the value null to indicate that the key is not in the table.
     return null;  
  }

  public void remove(Object key) {  
        // Remove the key and its associated value from the table,
        // if the key occurs in the table.  If it does not occur,
        // then nothing is done.
     int bucket = hash(key);  // At what location should the key be?
     if (table[bucket] == null) {
          // There are no keys in that location, so key does not
          // occur in the table.  There is nothing to do, so return.
        return; 
     }
     if (table[bucket].key.equals(key)) {
          // If the key is the first node on the list, then
          // table[bucket] must be changed to eliminate the
          // first node from the list.
        table[bucket] = table[bucket].next;
        count--; // Remove new number of items in the table.
        return;
     }
      // We have to remove a node from somewhere in the middle
      // of the list, or at the end.  Use a pointer to traverse
      // the list, looking for a node that contains the
      // specified key, and remove it if it is found.
     ListNode prev = table[bucket];  // The node that precedes
                                     // curr in the list.  Prev.next
                                     // is always equal to curr.
     ListNode curr = prev.next;  // For traversing the list,
                                 // starting from the second node.
     while (curr != null && ! curr.key.equals(key)) {
        curr = curr.next;
        prev = curr;
     }
      // If we get to this point, then either curr is null,
      // or curr.key is equal to key.  In the later case,
      // we have to remove curr from the list.  Do this
      // by making prev.next point to the node after curr,
      // instead of to curr.  If curr is null, it means that
      // the key was not found in the table, so there is nothing
      // to do.
     if (curr != null) {
        prev.next = curr.next;
        count--;  // Record new number of items in the table.
     }
  }

  public boolean containsKey(Object key) {
        // Test whether the specified key has an associated value
        // in the table.
     int bucket = hash(key);  // In what location should key be?
     ListNode list = table[bucket];  // For traversing the list.
     while (list != null) {
           // If we find the key in this node, return true.
        if (list.key.equals(key))
           return true;
        list = list.next;
     }
      // If we get to this point, we know that the key does
      // not exist in the table.
     return false;
  }

  public int size() {
        // Return the number of key/value pairs in the table.
     return count;
  }

  private int hash(Object key) {
        // Compute a hash code for the key; key cannot be null.
        // The hash code depends on the size of the table as
        // well as on the value returned by key.hashCode().
     return (Math.abs(key.hashCode())) % table.length;
  }

  private void resize() {
        // Double the size of the table, and redistribute the
        // key/value pairs to their proper locations in the
        // new table.
     ListNode[] newtable = new ListNode[table.length*2];
     for (int i = 0; i < table.length; i++) {
           // Move all the nodes in linked list number i 
           // into the new table.  No new ListNodes are 
           // created.  The existing ListNode for each
           // key/value pair is moved to the newtable.
           // This is done by changing the "next" pointer
           // in the node and by making a pointer in the 
           // new table point to the node.
        ListNode list = table[i]; // For traversing linked list number i.
        while (list != null) {
              // Move the node pointed to by list to the new table.
           ListNode next = list.next;  // The is the next node in the list.
                                       // Remember it, before changing
                                       // the value of list!
           int hash = (Math.abs(list.key.hashCode())) % newtable.length;
                // hash is the hash code of list.key that is 
                // appropriate for the new table size.  The
                // next two lines add the node pointed to by list
                // onto the head of the linked list in the new table
                // at position number hash.
           list.next = newtable[hash];
           newtable[hash] = list;
           list = next;  // Move on to the next node in the OLD table.
        }
     }
     table = newtable;  // Replace the table with the new table.
  } // end resize()

} // end class HashTable

HashTable测试程序:
一个测试HashTable类的小程序。请注意,我从一个非常小的表开始,以便我可以轻松地测试resize()方法。

public class TestHashTable {

  public static void main(String[] args){
     HashTable table = new HashTable(2);
     String key,value;
     while (true) {
        System.out.println("\nMenu:");
        System.out.println("   1. test put(key,value)");
        System.out.println("   2. test get(key)");
        System.out.println("   3. test containsKey(key)");
        System.out.println("   4. test remove(key)");
        System.out.println("   5. show complete contents of hash table.");
        System.out.println("   6. EXIT");
        System.out.print("Enter your command:  ");
        switch ( TextIO.getlnInt()) {
           case 1:
              System.out.print("\n   Key = ");
              key = TextIO.getln();
              System.out.print("   Value = ");
              value = TextIO.getln();
              table.put(key,value);
              break;         
           case 2:
              System.out.print("\n   Key = ");
              key = TextIO.getln();
              System.out.println("   Value is " + table.get(key));
              break;         
           case 3:
              System.out.print("\n   Key = ");
              key = TextIO.getln();
              System.out.println("   containsKey(" + key + ") is " 
                                           + table.containsKey(key));
              break;         
           case 4:
              System.out.print("\n   Key = ");
              key = TextIO.getln();
              table.remove(key);
              break;         
           case 5:
              table.dump();
              break;
           case 6:
              return;  // End program by returning from main()         
           default:
              System.out.println("   Illegal command.");
              break;
        }
        System.out.println("\nHash table size is " + table.size());
     }
  }

} // end class TestHashTable

答案 2 :(得分:0)

前言:我不知道什么是可扩展散列。

根据我对这个wiki(http://en.wikipedia.org/wiki/Extendible_hashing)的理解,它可以使用最多两次查找进行搜索,您可能希望查看Bernstein DB(sg-cDB)的Java实现。 http://cr.yp.to/cdb.html

答案 3 :(得分:0)

可扩展哈希的Java实现: http://en.wikibooks.org/wiki/Data_Structures/Hash_Tables#A_Java_implementation_of_extendible_hashing

  

正如srini.venigalla所说......伯恩斯坦的sg-cDB很好。您可以在GitHub中找到由Michael Alyn Miller制作的纯Java的移植版CDB:https://github.com/malyn/sg-cdb

答案 4 :(得分:0)

// Java program to demonstrate implementation of our
// own hash table with chaining for collision detection
import java.util.ArrayList;

// A node of chains
class HashNode<K, V>
{
    K key;
    V value;

    // Reference to next node
    HashNode<K, V> next;

    // Constructor
    public HashNode(K key, V value)
    {
        this.key = key;
        this.value = value;
    }
}

// Class to represent entire hash table
class Map<K, V>
{
    // bucketArray is used to store array of chains
    private ArrayList<HashNode<K, V>> bucketArray;

    // Current capacity of array list
    private int numBuckets;

    // Current size of array list
    private int size;

    // Constructor (Initializes capacity, size and
    // empty chains.
    public Map()
    {
        bucketArray = new ArrayList<>();
        numBuckets = 10;
        size = 0;

        // Create empty chains
        for (int i = 0; i < numBuckets; i++)
            bucketArray.add(null);
    }

    public int size() { return size; }
    public boolean isEmpty() { return size() == 0; }

    // This implements hash function to find index
    // for a key
    private int getBucketIndex(K key)
    {
        int hashCode = key.hashCode();
        int index = hashCode % numBuckets;
        return index;
    }

    // Method to remove a given key
    public V remove(K key)
    {
        // Apply hash function to find index for given key
        int bucketIndex = getBucketIndex(key);

        // Get head of chain
        HashNode<K, V> head = bucketArray.get(bucketIndex);

        // Search for key in its chain
        HashNode<K, V> prev = null;
        while (head != null)
        {
            // If Key found
            if (head.key.equals(key))
                break;

            // Else keep moving in chain
            prev = head;
            head = head.next;
        }

        // If key was not there
        if (head == null)
            return null;

        // Reduce size
        size--;

        // Remove key
        if (prev != null)
            prev.next = head.next;
        else
            bucketArray.set(bucketIndex, head.next);

        return head.value;
    }

    // Returns value for a key
    public V get(K key)
    {
        // Find head of chain for given key
        int bucketIndex = getBucketIndex(key);
        HashNode<K, V> head = bucketArray.get(bucketIndex);

        // Search key in chain
        while (head != null)
        {
            if (head.key.equals(key))
                return head.value;
            head = head.next;
        }

        // If key not found
        return null;
    }

    // Adds a key value pair to hash
    public void add(K key, V value)
    {
        // Find head of chain for given key
        int bucketIndex = getBucketIndex(key);
        HashNode<K, V> head = bucketArray.get(bucketIndex);

        // Check if key is already present
        while (head != null)
        {
            if (head.key.equals(key))
            {
                head.value = value;
                return;
            }
            head = head.next;
        }

        // Insert key in chain
        size++;
        head = bucketArray.get(bucketIndex);
        HashNode<K, V> newNode = new HashNode<K, V>(key, value);
        newNode.next = head;
        bucketArray.set(bucketIndex, newNode);

        // If load factor goes beyond threshold, then
        // double hash table size
        if ((1.0*size)/numBuckets >= 0.7)
        {
            ArrayList<HashNode<K, V>> temp = bucketArray;
            bucketArray = new ArrayList<>();
            numBuckets = 2 * numBuckets;
            size = 0;
            for (int i = 0; i < numBuckets; i++)
                bucketArray.add(null);

            for (HashNode<K, V> headNode : temp)
            {
                while (headNode != null)
                {
                    add(headNode.key, headNode.value);
                    headNode = headNode.next;
                }
            }
        }
    }

    // Driver method to test Map class
    public static void main(String[] args)
    {
        Map<String, Integer>map = new Map<>();
        map.add("this",1 );
        map.add("coder",2 );
        map.add("this",4 );
        map.add("hi",5 );
        System.out.println(map.size());
        System.out.println(map.remove("this"));
        System.out.println(map.remove("this"));
        System.out.println(map.size());
        System.out.println(map.isEmpty());
    }
}

答案 5 :(得分:0)

private ITEM[] st;  private int N, M;  ST(int maxN)  { N = 0; M = 4; st = new ITEM[M]; }  private void expand()  {  ITEM[] t = st;  N = 0; M = M+M; st = new ITEM[M];  for (int i = 0; i < M/2; i++)  if (t[i] != null) insert(t[i]);  }  void insert(ITEM x)  { int i = hash(x.key(), M);  while (st[i] != null) i = (i+1) % M;  st[i] = x;  if (N++ >= M/2) expand();  }

答案 6 :(得分:0)

/*
      A little program to test the HashTable class.  Note that I
      start with a really small table so that I can easily test
      the resize() method.
   */

   public class TestHashTable {

      public static void main(String[] args){
         HashTable table = new HashTable(2);
         String key,value;
         while (true) {
            System.out.println("\nMenu:");
            System.out.println("   1. test put(key,value)");
            System.out.println("   2. test get(key)");
            System.out.println("   3. test containsKey(key)");
            System.out.println("   4. test remove(key)");
            System.out.println("   5. show complete contents of hash table.");
            System.out.println("   6. EXIT");
            System.out.print("Enter your command:  ");
            switch ( TextIO.getlnInt()) {
               case 1:
                  System.out.print("\n   Key = ");
                  key = TextIO.getln();
                  System.out.print("   Value = ");
                  value = TextIO.getln();
                  table.put(key,value);
                  break;         
               case 2:
                  System.out.print("\n   Key = ");
                  key = TextIO.getln();
                  System.out.println("   Value is " + table.get(key));
                  break;         
               case 3:
                  System.out.print("\n   Key = ");
                  key = TextIO.getln();
                  System.out.println("   containsKey(" + key + ") is " 
                                               + table.containsKey(key));
                  break;         
               case 4:
                  System.out.print("\n   Key = ");
                  key = TextIO.getln();
                  table.remove(key);
                  break;         
               case 5:
                  table.dump();
                  break;
               case 6:
                  return;  // End program by returning from main()         
               default:
                  System.out.println("   Illegal command.");
                  break;
            }
            System.out.println("\nHash table size is " + table.size());
         }
      }

   } // end class TestHashTable

答案 7 :(得分:0)

Hashtable implements a key value pair kind of collection
*/
import java.util.*;
public class HashtableDemo {
  static String newLine = System.getProperty("line.separator");
  public static void main(String[] args) {

    System.out.println(newLine + "Hashtable in Java" + newLine);
    System.out.println("-----------------------" + newLine);
    System.out.println("Adding items to the Hashtable" + newLine);
    //Creating Hashtable object
    //dictionary can be created using HashTable object
    //as dictionary is an abstract class
    Hashtable ht = new Hashtable();

    //you add elements to Hashtable using put method
    //put(key, value)
    ht.put("Java", 1);
    ht.put(".NET", 2);
    ht.put("Javascript", 3 );
    ht.put("HTML", 4);

    //You will see that the items will be arranged as per the hash function
    System.out.println(newLine + "Items in the Hashtable..." + ht + newLine);
    System.out.println("-----------------------" + newLine);

    //looping through all the elements in hashtable
    String str;
    //you can retrieve all the keys in hashtable using .keys() method
    Enumeration names = ht.keys();
      while(names.hasMoreElements()) {
          //next element retrieves the next element in the dictionary
         str = (String) names.nextElement();
         //.get(key) returns the value of the key stored in the hashtable
         System.out.println(str + ": " + ht.get(str) + newLine);
      }
  }
}