Question

我使用Sequelize with Express并从本教程开始： http://sequelizejs.com/articles/express

我希望用户拥有任何用户（朋友列表）

这是我的用户类：

    module.exports = function(sequelize, DataTypes) {
  var User = sequelize.define('User', {
    username : {type:DataTypes.STRING, allowNull:false,unique: true},
    email : {type:DataTypes.STRING, allowNull:false,unique:true,validate:{isEmail : true},msg:"Email must be valid."},
    password : {type:DataTypes.STRING,allowNull:false,validate:{len:[6,],msg:"Password length > 5."}},
    score : DataTypes.INTEGER,
    timeplay : DataTypes.BIGINT,
    timeaverage : DataTypes.INTEGER,
    nbrnotfoundword : DataTypes.INTEGER,
    nbrnotfound : DataTypes.INTEGER
  }, 
  {
    associate: function(models) {
        User.hasMany(models.User)

    }


    })

  return User
}

User.hasMany（models.User）给了我这个错误：

/home/damien/Documents/app/node_modules/sequelize/lib/associations/has-many.js:172
      this.through.init(this.through.daoFactoryManager)
                   ^
TypeError: Object true has no method 'init'
    at module.exports.HasMany.injectAttributes (/home/damien/Documents/app/node_modules/sequelize/lib/associations/has-many.js:172:20)
    at Mixin.hasMany (/home/damien/Documents/app/node_modules/sequelize/lib/associations/mixin.js:53:68)
    at Object.sequelize.define.associate (/home/damien/Documents/app/models/user.js:18:11)
    at module.exports.lodash.extend.sequelize (/home/damien/Documents/app/models/index.js:20:27)
    at Array.forEach (native)
    at Object.<anonymous> (/home/damien/Documents/app/models/index.js:18:17)
    at Module._compile (module.js:456:26)
    at Object.Module._extensions..js (module.js:474:10)
    at Module.load (module.js:356:32)
    at Function.Module._load (module.js:312:12)

寻求帮助。

Answer 1

这很可能是因为在定义之前您使用了用户。

请改为尝试：

module.exports = function(sequelize, DataTypes) {

  var User = sequelize.define('User', {
    username : {type:DataTypes.STRING, allowNull:false,unique: true},
    email : {type:DataTypes.STRING, allowNull:false,unique:true,validate:{isEmail : true}, msg:"Email must be valid."},
    password : {type:DataTypes.STRING,allowNull:false,validate:{len:[6,],msg:"Password length > 5."}},
    score : DataTypes.INTEGER,
    timeplay : DataTypes.BIGINT,
    timeaverage : DataTypes.INTEGER,
    nbrnotfoundword : DataTypes.INTEGER,
    nbrnotfound : DataTypes.INTEGER
  });

  User.hasMany(User);

  return User;
}

Answer 2

我发现了问题：

var Sequelize = require('sequelize-mysql').sequelize

而不是

var Sequelize = require('sequelize')

Sequelize：对象true没有方法'init'

2 个答案: