SQL SERVER - 无法解决与操作相等的排序规则冲突

时间:2014-01-21 15:54:20

标签: sql-server active-directory

请告诉我,我应该放COLLATE DATABASE_DEFAULT

创建以下视图?

我做了搜索,发现我应该把where子句放在每一边。我尝试了所有的可能性,但我仍然得到同样的错误,说“无法在等于操作的情况下解决”SQL_Latin1_General_CP1_CI_AS“和”Latin1_General_CI_AS“之间的整理冲突。'

以下是查询:

CREATE view [dbo].[NewADUsers] AS SELECT 
tbl.objectGUID AS UserGUID 
, SUBSTRING(tbl.Email, CHARINDEX('@', tbl.Email)+1,
LEN(tbl.Email)- CHARINDEX('@',tbl.Email)) AS 'DomainName'
, gd.GroupName, dsg.DefaultSubGroup, tbl.sAMAccountName
, tbl.sAMAccountName AS UserName, tbl.Email AS Email
FROM (
SELECT  
"SAMAccountName" AS sAMAccountName, "mail" AS Email, "objectGUID" AS objectGUID
    FROM OpenQuery(
        ADSI,
        'SELECT SAMAccountName, mail, objectGUID
        FROM ''LDAP://mydomain.com/OU=blah,OU=blah,OU=blah,DC=mydomain,DC=com''   
        WHERE objectClass=''User''')) 
    AS tbl
INNER JOIN dbo.GroupsDomains gd ON gd.DomainName = SUBSTRING(tbl.Email, CHARINDEX('@', tbl.Email)+1, LEN(tbl.Email)- CHARINDEX('@',tbl.Email))
LEFT JOIN dbo.DefaultSubGroups dsg ON gd.GroupName = dsg.GroupName  
WHERE tbl.objectGUID NOT IN (SELECT UserGUID FROM dbo.Users)

GO

1 个答案:

答案 0 :(得分:1)

我一直在阅读有关此问题的几篇论文。最后,我无法理解这个错误是如何产生的。

我的解决方案是:
将COLLATE DATABASE_DEFAULT置于连接条件... ...

INNER JOIN dbo.GroupsDomains gd ON gd.DomainName = SUBSTRING(tbl.Email, CHARINDEX('@', tbl.Email)+1, 
LEN(tbl.Email)- CHARINDEX('@',tbl.Email))
LEFT JOIN dbo.DefaultSubGroups dsg 

-- Modified this next line:
ON gd.GroupName COLLATE DATABASE_DEFAULT = dsg.GroupName COLLATE DATABASE_DEFAULT

WHERE tbl.objectGUID NOT IN (SELECT UserGUID FROM dbo.Users)
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