Question

我正在为我的大学编写一个关于编程课程的小项目。它涉及从谷歌api（JSON）获取数据并向用户提供一些信息。

function compare($city, $start, $destination)
{
    // merge city with start and destination
    $city_start = $start . ', ' . $city;
    $city_destination = $destination . ', ' . $city;

    // reject symbols that start with ^
    if (preg_match("/^\^/", $city) OR preg_match("/^\^/", $start) OR preg_match("/^\^/", $destination))
    {
        return false;
    }

    // reject symbols that contain commas
    if (preg_match("/,/", $city) OR preg_match("/,/", $start) OR preg_match("/,/", $city))
    {
        return false;
    }

    // determine url
    $url = "http://maps.googleapis.com/maps/api/directions/json?origin=$city_start&destination=$city_destination&sensor=false&mode=bicycling";
    echo $url;

    // open connection to google maps
    $curl_session = curl_init($url);
    curl_setopt($curl_session, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl_session, CURLOPT_HEADER, 0);

    // get data from json output
    $json = curl_exec($curl_session);
    curl_close($curl_session);
    var_dump($json);
}

上面的代码在var_dump返回400错误，其中$ city，$ start和$ destination分别开始地址，目的地地址和地址所在的城市。存储在$ url中的url工作正常，并在浏览器中输入时返回JSON输出。

谁能告诉我我做错了什么？

干杯，

d

Answer 1

您可以尝试urlencode变量：

$city_start = urlencode($start . ', ' . $city);
$city_destination = urlencode($destination . ', ' . $city);

Var_Dump（错误400 - 错误请求）

1 个答案: