Question

我正在尝试在RHEL6上运行mod_wsgi应用程序，无论我如何尝试，我似乎都无法建立FIFO。我认为这可能是一个权限问题，但我无法弄明白。

这是httpd配置的相关部分：

WSGIDaemonProcess loris user=loris group=loris processes=10 threads=15 maximum-requests=10000
WSGISocketPrefix /var/run/wsgi
WSGIProcessGroup loris

<Directory /var/www/loris>
    Order allow,deny
    Allow from all
</Directory>

这是一个最低工作示例（Python 2.7）：

import getpass
import os
import subprocess

def application(environ, start_response):
    status = '200 OK'
    response_headers = [('Content-type', 'text/plain')]

    path = '/var/www/loris'

    c = ''
    c += 'user: %s\n' % getpass.getuser() # prints 'loris', as expected

    # try opening a file; works fine
    f = open('%s/open.txt' % path, 'w')
    f.write('ok\n')
    f.close()
    c += 'we can write a file\n'

    # try 'touching' a file; works fine
    call = '/bin/touch %s/touch.txt' % path
    s = subprocess.check_call(call, shell=True)
    c += '/bin/touch status = %s' % s    # prints 0, as expected

    # try shelling out to mkfifo; doesn't work
    # Error msg: '/usr/bin/mkfifo: cannot create fifo `/var/www/loris/binfifo':
    #   Permission denied'
    call = '/usr/bin/mkfifo %s/binfifo' % path
    s = subprocess.check_call(call, shell=True)
    # throws a 500 error

    # try os.mkfifo(); doesn't work either
    fifo_path = '%s/os_fifo' % path
    os.mkfifo(fifo_path)
    s = subprocess.check_call(call, shell=True)
    # again, 'OSError: [Errno 13] Permission denied'

    start_response(status, response_headers)
    return c

显然，用户有权写入目录，但看起来mkfifo特别是问题（因为/bin/touch工作正常）。我可以自己做一个fifo，所以文件系统支持它们。我也可以用py os.mkfifo()在python shell中以两种方式（shelling out和loris）制作fifos。我认为这与mod_wsgi和权限有关，但我想不出还有什么可以尝试。

mod_wsgi无法运行mkfifo？

0 个答案: