Question

您好我有这个代码从python列表中选择项目。问题是一旦它循环

CODE：

import re
name = input
while True:
    name = input("Please enter your search term here:").lower()
    def FindName(name,list1):
        """ searches for a pattern in the list, returns the complete list entry. Is case       sensitive.
May return incomplete value if ' is in the list value (ie confucius's)"""
    if name in list1:
        return name
    else:
        string1 = str(list1).replace('"',"'")
        pattern = re.compile("[']"+name+"[^']*")
        match = re.search(pattern,string1)
        if match:
            if match.group().lstrip("'") in list1:
                return match.group().lstrip("'")
            else:
                print 'Fail %s' %match.group().lstrip("'")
                return None
        else:
            return ' '.join(name2) 
    china=['In', 'China', 'people', 'teach',"Confusius's",
    'teachings','dilligently.','Those',"Confusius''s",
    'teachings','are','called','Taoism.']
    india=['India', 'bopal', 'mahindra', 'gujarat',"gandhi's",
    'bombay',"Gandhi",]        ]

    name2 = name[:]
    this= ' '.join(name2)
    print FindName(this,china)
    for item in china:            
        print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]
    this = ' '.join(name2)
    for item in india:
        print [(i,x) for (i,x) in enumerate(india) if x.startswith(this)]
    this = ' '.join(name2)
    for item in india:
        print [(i,x) for (i,x) in enumerate(india) if x.endswith(this)]
    this = ' '.join(name2)
    for item in india:
        print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]
     loop continues......

问题在于我试图在循环中设置中断，但它仍会在每个循环上打印：print [(i,x) for (i,x) in enumerate...，因为它会循环到循环中。如何使它循环遍历语句，但只打印预期的项目而不循环和打印print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]等？

Answer 1

我认为你为每个结果加倍了你的打印。而不是：

for item in china:            
    print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]  # will print relevant index and item of china once for every item in china

试试这个：

for index, item in enumerate(china):
    if item.startswith(this):
        print (index, item)  # will print each relevant index and item in china only once

或者这个：

print [(i,x) for (i,x) in enumerate(china) if x.startswith(this)]  # no for-loop

每个for循环

。如果您想要摆脱较大的while循环，则需要在for循环之外插入break ：

while True:
    ...
    if <something>:
        break
    for ...

虽然循环不能正常工作

1 个答案: