我正在使用Xpath和Java。
XML有很多OBJECT_TYPES
,每个对象类型都有属性和参数。
每个属性和参数都有元素。
如何从我的XML文件中执行以下操作。
我想知道如何使用XPATH字符串表达式选择所有属性元素,具体取决于OBJECT_TYPE
字符串的名称。对象类型字符串名称取决于用户从列表中选择的名称。
我该怎么做?
应该是这样的:
String expression = "/getObjType()/prop/*";
但是getObjectType
是一种方法,所以我不能在字符串表达式中使用它。
XML看起来像这样:
<type>
<OBJECT_TYPE>SiteData</OBJECT_TYPE>
<prop>
<DESCRIPTION>Site parameters</DESCRIPTION>
<PARENT>NULL</PARENT>
<VIRTUAL>0</VIRTUAL>
<VISIBLE>1</VISIBLE>
<PICTURE>NULL</PICTURE>
<HELP>10008</HELP>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<NAME_FORMAT>NULL</NAME_FORMAT>
</prop>
<param>
<PARAMETER>blabla</PARAMETER>
<DATA_TYPE>INTEGER</DATA_TYPE>
<DESCRIPTION>blaba</DESCRIPTION>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<ORDER1>1</ORDER1>
<NESTED>0</NESTED>
<DEFAULT1>NULL</DEFAULT1>
<FORMAT>0:16382</FORMAT>
</param>
<OBJECT_TYPE>Data</OBJECT_TYPE>
<prop>
<DESCRIPTION>Site parameters</DESCRIPTION>
<PARENT>NULL</PARENT>
<VIRTUAL>0</VIRTUAL>
<VISIBLE>1</VISIBLE>
<PICTURE>NULL</PICTURE>
<HELP>10008</HELP>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<NAME_FORMAT>NULL</NAME_FORMAT>
</prop>
<param>
<PARAMETER>gmgm</PARAMETER>
<DATA_TYPE>INTEGER</DATA_TYPE>
<DESCRIPTION>babla</DESCRIPTION>
<MIN_NO>1</MIN_NO>
<MAX_NO>1</MAX_NO>
<ORDER1>1</ORDER1>
<NESTED>0</NESTED>
<DEFAULT1>NULL</DEFAULT1>
<FORMAT>0:16382</FORMAT>
</param>
</type>
因此,根据什么是Object_type的名称,我想得到thoose属性,我列出了122个对象类型,所以我必须使用varible来选择用户选择的那个。
public class PropXMLParsing {
static PropXMLParsing instance = null;
private List<String> list = new ArrayList<String>();
ObjType obj = new ObjType();
public static PropXMLParsing getInstance() {
if (instance == null) {
instance = new PropXMLParsing();
try {
instance.ParserForObjectTypes();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
}
}
return instance;
}
public void ParserForObjectTypes() throws SAXException, IOException,
ParserConfigurationException {
try {
FileInputStream file = new FileInputStream(new File(
"xmlFiles/CoreDatamodel.xml"));
DocumentBuilderFactory builderFactory = DocumentBuilderFactory
.newInstance();
builderFactory.setNamespaceAware(true);
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document xmlDocument = builder.parse(file);
XPath xp = XPathFactory.newInstance().newXPath();
final Map<String, Object> vars = new HashMap<String, Object>();
xp.setXPathVariableResolver(new XPathVariableResolver() {
public Object resolveVariable(QName name) {
return vars.get(name.getLocalPart());
}
});
XPathExpression expr = xp
.compile("/type/OBJECT_TYPE[. = $type]/following-sibling::prop[1]");
vars.put("type", obj.getObjectType());
NodeList objectProps = (NodeList) expr.evaluate(xmlDocument,
XPathConstants.NODESET);
System.out.println(objectProps);
for (int i = 0; i < objectProps.getLength(); i++) {
System.out.println(objectProps.item(i).getFirstChild()
.getNodeValue());
list.add(objectProps.item(i).getFirstChild().getNodeValue());
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (XPathExpressionException e) {
e.printStackTrace();
}
}
public String convertListToString() {
StringBuilder sb = new StringBuilder();
if (list.size() > 0) {
sb.append(list.get(0));
for (int i = 1; i < list.size(); i++) {
sb.append(list.get(i));
}
}
return sb.toString();
}
}
第二个解决方案我已经尝试过,aint既不会在控制台中打印任何内容。
public void ParserForObjectTypes() throws SAXException, IOException,
ParserConfigurationException {
try {
FileInputStream file = new FileInputStream(new File(
"xmlFiles/CoreDatamodel.xml"));
DocumentBuilderFactory builderFactory = DocumentBuilderFactory
.newInstance();
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document xmlDocument = builder.parse(file);
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList) xPath.compile(
"//OBJECT_TYPE[text() = '" + obj.getObjectType()
+ "']/following-sibling::prop[1]/*").evaluate(
xmlDocument, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
System.out.println(nodeList.item(i).getNodeName() + " = "
+ nodeList.item(i).getTextContent());
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (XPathExpressionException e) {
e.printStackTrace();
}
}
答案 0 :(得分:2)
如果您要提取属于特定prop
的{{1}},您可以使用
OBJECT_TYPE
在Java中,您可以使用字符串连接动态构建此XPath表达式,但如果您使用的库可以支持,那么使用XPath变量会更安全(您不会在问题中说明您的库是什么)重新使用)。例如/type/OBJECT_TYPE[. = 'some type']/following-sibling::prop[1]
javax.xml.xpath
答案 1 :(得分:1)
此XPATH将选择prop
元素中OBJECT_TYPE
元素内的所有元素,文本为SiteData
:
//OBJECT_TYPE[text() = 'SiteData']/following-sibling::prop[1]/*
要更改正在选择的OBJECT_TYPE
,只需在代码中构建XPATH:
String xpath = "//OBJECT_TYPE[text() = '" + getObjType() + "']/following-sibling::prop[1]/*"
这导致代码如下:
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList nodeList = (NodeList)xPath.compile("//OBJECT_TYPE[text() = '" + getObjType() + "']/following-sibling::prop[1]/*").evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++)
{
System.out.println(nodeList.item(i).getNodeName() + " = " + nodeList.item(i).getTextContent());
}
考虑到问题中的XML以及getObjType()
何时返回SiteData
打印:
DESCRIPTION = Site parameters
PARENT = NULL
VIRTUAL = 0
VISIBLE = 1
PICTURE = NULL
HELP = 10008
MIN_NO = 1
MAX_NO = 1
NAME_FORMAT = NULL